matrix = [[0 for i in range(7)] for j in range(4)]for i in range(4): for j in range(i, 7 - i): matrix[i][j] = j - i + 1 matrix[3-i][j] = j - i + 1print(matrix)将这串代码写成换行的形式
时间: 2024-04-20 13:27:15 浏览: 110
matrix = [[0 for i in range(7)] for j in range(4)]
for i in range(4):
for j in range(i, 7 - i):
matrix[i][j] = j - i + 1
matrix[3-i][j] = j - i + 1
print(matrix)
相关问题
matrix = [[0 for i in range(10)] for j in range(10)]的结果
这行代码会创建一个10行10列的二维数组(matrix),初始值都为0。可以用以下代码来验证结果:
```
matrix = [[0 for i in range(10)] for j in range(10)]
print(matrix)
```
输出结果为:
```
[[0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0],
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]]
```
可以看到,matrix是一个10行10列的二维数组,初始值都为0。
for i in range(im.shape[0]):
This is a Python code snippet that uses a loop to iterate over the rows of a 2D array or matrix called "im" and perform some operation on each row. The "range(im.shape[0])" function generates a sequence of integers from 0 to the number of rows in "im" (i.e. the first dimension of the array), and the loop variable "i" takes on each of these values in turn. The code inside the loop can access and manipulate the values in the i-th row of "im" using indexing, such as "im[i, j]" to access the j-th element in that row.
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