ros中写一个发布一条由四个点确定一条贝塞尔曲线的python代码
时间: 2024-05-07 10:16:38 浏览: 132
机器人操作系统(ROS)经典中文教程.pdf
以下是一个发布一条由四个点确定一条贝塞尔曲线的Python代码示例:
```
import rospy
from geometry_msgs.msg import Point, Pose, Quaternion, Twist, Vector3
from nav_msgs.msg import Path
from scipy.special import comb
import numpy as np
def publish_bezier_curve(path_pub, points):
# 计算贝塞尔曲线的控制点
control_points = []
for t in np.linspace(0, 1, len(points)):
p = np.zeros(2)
for i, point in enumerate(points):
p += comb(len(points)-1, i) * (1-t)**(len(points)-1-i) * t**i * np.array([point.x, point.y])
control_points.append(Point(p[0], p[1], 0))
# 发布路径消息
path = Path()
path.header.frame_id = "map"
for point in control_points:
pose = Pose()
pose.position = point
path.poses.append(pose)
path_pub.publish(path)
if __name__ == '__main__':
rospy.init_node('bezier_curve_publisher')
path_pub = rospy.Publisher('/path', Path, queue_size=10)
points = [Point(0, 0, 0), Point(1, 1, 0), Point(2, -1, 0), Point(3, 0, 0)]
publish_bezier_curve(path_pub, points)
rospy.spin()
```
希望这个代码能够帮助你!
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