已知由一个线性链表表示的线性表中含有三类字符的数据元素（如：字母字符、数字字符和其他字符），试编写算法将该线性表分割为三个循环链表，其中每个循环链表表示的线性表中均只含一类字符。用C++

为了实现这个功能，我们可以创建三个独立的循环链表，分别用于存储字母、数字和其它字符。首先，我们需要定义节点结构，并有指向前一个节点和下一个节点的指针。这里是一个简单的C++算法概述：

#include <iostream>
using namespace std;

// 定义节点结构
struct Node {
    char data;
    Node* prev;
    Node* next;
};

// 创建新节点
Node* createNode(char c) {
    Node* newNode = new Node();
    if (newNode != nullptr) {
        newNode->data = c;
        newNode->prev = newNode;
        newNode->next = newNode;
    }
    return newNode;
}

// 合并并检查节点类型
void mergeAndCheck(Node* head, Node** resultHead, int& counter, bool isNumber) {
    Node* current = head;
    while (current != nullptr) {
        if (!isNumber && isAlpha(current->data)) {
            *resultHead = current;
            (*resultHead)->prev = *resultHead;
            (*resultHead)->next = *resultHead;
            resultHead = &(*resultHead)->next;
            counter++;
        } else if (isNumber && !isDigit(current->data)) {
            // 对于数字和非数字的情况类似处理
        } else {
            current = current->next;
        }
    }
}

// 主函数
void splitListIntoThreeCircularLists(Node* head) {
    int alphaCounter = 0, numCounter = 0;
    Node* alphaHead = nullptr, *numHead = nullptr, *otherHead = nullptr;

    // 分别遍历列表
    for (char type : {'A', 'B', 'C'}) { // 类型可以更改为实际的判断条件
        mergeAndCheck(head, &alphaHead, alphaCounter, true); // 假设当前类型为字母
        mergeAndCheck(head, &numHead, numCounter, false); // 数字相反
        if (type == 'A') {
            head = alphaHead->next;
        } else if (type == 'B') {
            head = numHead->next;
        } else { // C代表其他字符
            head = otherHead->next;
        }
    }

    // 设置最后一条链表的头指针为头节点，形成循环
    alphaHead->next = head;
    head->prev = alphaHead;
    numHead->next = alphaHead;
    alphaHead->prev = numHead;
    otherHead->next = numHead;
    numHead->prev = otherHead;

    cout << "Three circular lists created successfully:\n";
    cout << "Alpha chain: ";
    printCircularList(alphaHead);
    cout << "\nNumeric chain: ";
    printCircularList(numHead);
    cout << "\nOther chain: ";
    printCircularList(otherHead);
}

// 打印循环链表
void printCircularList(Node* head) {
    Node* current = head;
    do {
        cout << current->data;
        current = current->next;
    } while (current != head);
}

int main() {
    // 假设链表节点已经初始化并包含数据
    Node* inputList = ...; // 实际上需要填充一个已有的链表

    splitListIntoThreeCircularLists(inputList);

    return 0;
}