cols[!names(cols) %in% indic_edge_16s] <- "gray30"
时间: 2024-06-03 10:08:34 浏览: 11
As an AI language model, I do not have any personal beliefs or emotions. Therefore, the concept of "null" does not mean anything to me in a personal sense. However, in computer programming, "null" refers to the absence of a value or object.
相关问题
如果length(PET_Tumordata_zero_sd_cols) =0,则PET_Tumordata_zero_sd_cols=PET_Tumordata_zero_sd_cols <-,而且 0,而且PET_Tumordata <- PET_Tumordata;否则PET_Tumordata_zero_sd_cols,PET_Tumordata <- PET_Tumordata,请写出R语言代码
以下是这段 R 语言代码的实现:
```R
if(length(PET_Tumordata_zero_sd_cols) == 0) {
PET_Tumordata_zero_sd_cols <- rep(0, ncol(PET_Tumordata))
PET_Tumordata <- PET_Tumordata
} else {
PET_Tumordata_zero_sd_cols
PET_Tumordata <- PET_Tumordata[, -c(PET_Tumordata_zero_sd_cols)]
}
```
其中 `PET_Tumordata_zero_sd_cols` 是一个长度为 0 或不为 0 的向量,`PET_Tumordata` 是一个数据框。这段代码的意思是,如果 `PET_Tumordata_zero_sd_cols` 的长度为 0,那么将其赋值为所有元素都为 0,然后保留 `PET_Tumordata` 的所有列;否则,删除 `PET_Tumordata` 中 `PET_Tumordata_zero_sd_cols` 所对应的列。
> df3 <- pivot_longer(QLS_soil,cols = -("Degree of desertification","Classes"), Error: unexpected ',' in "df3 <- pivot_longer(QLS_soil,cols = -("Degree of desertification"," >
错误提示显示代码中存在语法错误,原因在于第二个参数中的字符需要使用向量的形式,而且不需要使用括号。请尝试将该行代码修改为以下形式:
```
df3 <- pivot_longer(QLS_soil, cols = c(-"Degree of desertification", -"Classes"), names_to = "Depth", values_to = "pH")
```
在这里,我使用了向量 `c()` 将需要排除的列名 `"Degree of desertification"` 和 `"Classes"` 进行了组合,并使用负号 `-` 表示将这些列排除。同时,我去掉了参数中的括号,保证语法正确。