c语言用二叉链表创建一个深度为4的非完全二叉树，并用先序和层序遍历

这是一个技术问题，我可以为您解答。以下是代码示例：

#include <stdio.h>
#include <string.h>
#include <stdlib.h>

typedef struct Node {
    char data;
    struct Node* lchild;
    struct Node* rchild;
} Node;

Node* create(char data) {
    Node* node = (Node*)malloc(sizeof(Node));
    node->data = data;
    node->lchild = NULL;
    node->rchild = NULL;
    return node;
}

void preOrder(Node* node) {
    if (node == NULL) {
        return;
    }
    printf("%c ", node->data);
    preOrder(node->lchild);
    preOrder(node->rchild);
}

void levelOrder(Node* root) {
    Node** queue = (Node**)malloc(sizeof(Node*) * 100);
    int head = 0;
    int tail = 0;
    queue[tail++] = root;
    while (head != tail) {
        Node* node = queue[head++];
        printf("%c ", node->data);
        if (node->lchild != NULL) {
            queue[tail++] = node->lchild;
        }
        if (node->rchild != NULL) {
            queue[tail++] = node->rchild;
        }
    }
}

int main() {
    Node* root = create('A');
    Node* b = create('B');
    Node* c = create('C');
    Node* d = create('D');
    Node* e = create('E');
    Node* f = create('F');
    Node* g = create('G');
    Node* h = create('H');
    Node* i = create('I');
    Node* j = create('J');
    Node* k = create('K');
    Node* l = create('L');
    Node* m = create('M');

    root->lchild = b;
    root->rchild = c;
    b->lchild = d;
    b->rchild = e;
    c->lchild = f;
    c->rchild = g;
    d->lchild = h;
    e->rchild = i;
    f->rchild = j;
    g->rchild = k;
    h->rchild = l;
    k->lchild = m;

    printf("先序遍历：");
    preOrder(root);
    printf("\n");

    printf("层序遍历：");
    levelOrder(root);
    printf("\n");

    return 0;
}

上面的代码创建了一个深度为 4 的非完全二叉树，使用先序遍历和层序遍历分别输出了每个节点的值。您可以根据需要修改节点数据和结构来创建其他树形结构。