请用C语言实现反向reverse一个单向链表编程
时间: 2024-02-24 07:55:41 浏览: 21
好的,以下是用C语言实现反向reverse一个单向链表的代码:
```c
#include <stdio.h>
#include <stdlib.h>
// 定义单向链表结构体
typedef struct Node {
int data;
struct Node* next;
} Node;
// 创建节点函数
Node* createNode(int data) {
Node* node = (Node*)malloc(sizeof(Node));
node->data = data;
node->next = NULL;
return node;
}
// 反向函数
Node* reverse(Node* head) {
Node* prev = NULL;
Node* current = head;
Node* next = NULL;
while (current != NULL) {
next = current->next;
current->next = prev;
prev = current;
current = next;
}
return prev;
}
// 打印函数
void printList(Node* head) {
Node* current = head;
while (current != NULL) {
printf("%d ", current->data);
current = current->next;
}
printf("\n");
}
int main() {
// 创建链表
Node* head = createNode(1);
head->next = createNode(2);
head->next->next = createNode(3);
head->next->next->next = createNode(4);
head->next->next->next->next = createNode(5);
printf("原链表:");
printList(head);
// 反向链表
head = reverse(head);
printf("反向链表:");
printList(head);
return 0;
}
```
运行结果如下:
```
原链表:1 2 3 4 5
反向链表:5 4 3 2 1
```