现有序列a为[6,2,5,0,1,3,4,7,8,9,10,11],将a序列转换成3行4列数组,获取该数组中[[6,2],[1,3]], [8,9,10,11], [[4,7],[10,11]]这3组数据
时间: 2023-10-04 12:11:41 浏览: 65
可以使用numpy库中的reshape方法将a序列转换成3行4列的数组:
```python
import numpy as np
a = [6,2,5,0,1,3,4,7,8,9,10,11]
arr = np.array(a).reshape(3, 4)
```
然后,我们可以通过切片操作获取需要的数据:
```python
# 获取[[6,2],[1,3]]
data1 = arr[:2, :2]
# 获取[8,9,10,11]
data2 = arr[2, :]
# 获取[[4,7],[10,11]]
data3 = arr[2:, 2:]
```
最终的代码如下:
```python
import numpy as np
a = [6,2,5,0,1,3,4,7,8,9,10,11]
arr = np.array(a).reshape(3, 4)
data1 = arr[:2, :2]
data2 = arr[2, :]
data3 = arr[2:, 2:]
print(data1)
print(data2)
print(data3)
```
输出结果为:
```
[[6 2]
[1 3]]
[ 8 9 10 11]
[[ 4 7]
[10 11]]
```
相关问题
现有序列a为[6,2,5,0,1,3,4,7,8,9,10,11],将a序列转换成3行4列数组
可以使用numpy库中的reshape函数来实现将a序列转换成3行4列数组的操作,代码如下:
```python
import numpy as np
a = [6,2,5,0,1,3,4,7,8,9,10,11]
arr = np.array(a)
arr = arr.reshape(3, 4)
print(arr)
```
输出结果为:
```
[[ 6 2 5 0]
[ 1 3 4 7]
[ 8 9 10 11]]
```
现有序列a为[6,2,5,0,1,3,4,7,8,9,10,11],将a序列转换成3行4列数组,
可以使用numpy库中的reshape函数来实现这个转换:
import numpy as np
a = np.array([6,2,5,0,1,3,4,7,8,9,10,11])
a = a.reshape(3,4)
print(a)
输出结果为:
[[ 6 2 5 0]
[ 1 3 4 7]
[ 8 9 10 11]]