import os folder_list = ['/path/to/folder1', '/path/to/folder2', '/path/to/folder3'] for folder_path in folder_list: for sub_folder in os.listdir(folder_path): sub_folder_path = os.path.join(folder_path, sub_folder) if os.path.isdir(sub_folder_path): for file_name in os.listdir(sub_folder_path): file_path = os.path.join(sub_folder_path, file_name) if os.path.isfile(file_path): print('{}\t{}'.format(os.path.basename(folder_path), file_name))在这个程序输出结果的基础上,改写,输出结果的上一级文件夹名
时间: 2024-03-20 11:42:41 浏览: 21
可以将 `os.path.basename(folder_path)` 改为 `os.path.basename(os.path.dirname(folder_path))`,这样就可以输出结果的上一级文件夹名了。改写后的程序如下:
```
import os
folder_list = ['/path/to/folder1', '/path/to/folder2', '/path/to/folder3']
for folder_path in folder_list:
for sub_folder in os.listdir(folder_path):
sub_folder_path = os.path.join(folder_path, sub_folder)
if os.path.isdir(sub_folder_path):
for file_name in os.listdir(sub_folder_path):
file_path = os.path.join(sub_folder_path, file_name)
if os.path.isfile(file_path):
print('{}\t{}'.format(os.path.basename(os.path.dirname(folder_path)), file_name))
```
注意,这里的 `/path/to/folder1` 等路径需要根据实际情况进行修改。