用Verilog HDL语言实现根据二十四进制小时计数器、六十进制分计数器、六十进制秒计数器的闹钟
时间: 2023-11-07 21:04:44 浏览: 100
基于FPGA用Verilog HDL语言实现的多功能数字钟
这个问题需要实现一个基于FPGA的闹钟,需要使用Verilog HDL语言来实现。下面是一个简单的实现示例。
```verilog
module clock(
input clk, // 时钟输入
input reset, // 复位输入
input set_alarm, // 闹钟设置输入
output reg alarm_on, // 闹钟开关输出
output reg [3:0] hour, minute, second, // 时间输出
output reg [3:0] alarm_hour, alarm_minute, alarm_second // 闹钟时间输出
);
reg [3:0] count_hour, count_minute, count_second; // 时、分、秒计数器
reg [3:0] alarm_count_hour, alarm_count_minute, alarm_count_second; // 闹钟时、分、秒计数器
// 时、分、秒计数器
always @(posedge clk or posedge reset) begin
if (reset) begin
count_hour <= 0;
count_minute <= 0;
count_second <= 0;
end else begin
if (count_second == 59) begin
count_second <= 0;
if (count_minute == 59) begin
count_minute <= 0;
if (count_hour == 23) begin
count_hour <= 0;
end else begin
count_hour <= count_hour + 1;
end
end else begin
count_minute <= count_minute + 1;
end
end else begin
count_second <= count_second + 1;
end
end
end
// 闹钟时、分、秒计数器
always @(posedge clk or posedge reset) begin
if (reset) begin
alarm_count_hour <= 0;
alarm_count_minute <= 0;
alarm_count_second <= 0;
end else if (set_alarm) begin
alarm_count_hour <= count_hour;
alarm_count_minute <= count_minute;
alarm_count_second <= count_second;
end
end
// 闹钟开关
always @(*) begin
if ((count_hour == alarm_count_hour) && (count_minute == alarm_count_minute) && (count_second == alarm_count_second)) begin
alarm_on <= 1;
end else if (alarm_on && (count_second == 0)) begin
alarm_on <= 0;
end else begin
alarm_on <= alarm_on;
end
end
// 时间输出
assign hour = count_hour;
assign minute = count_minute;
assign second = count_second;
// 闹钟时间输出
assign alarm_hour = alarm_count_hour;
assign alarm_minute = alarm_count_minute;
assign alarm_second = alarm_count_second;
endmodule
```
在这个示例中,时、分、秒计数器使用了一个 always 块实现,通过对时、分、秒进行递增操作来实现时间的计数。闹钟时、分、秒计数器则使用了另一个 always 块,通过对闹钟时、分、秒的设置和当前时间的比较来实现闹钟计数器。同时,还定义了一个闹钟开关标志,用于指示当前闹钟是否响铃。
需要注意的是,这个示例只是一个简单的实现,实际应用中还需要考虑更多的因素,如显示器、按键输入等。
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