js两个数组匹配相同的对象

方法一：使用循环嵌套

可以使用两个嵌套的循环来比较两个数组中的每个对象是否相同。

示例代码：

const arr1 = [{id: 1, name: 'John'}, {id: 2, name: 'Jane'}, {id: 3, name: 'Mike'}];
const arr2 = [{id: 2, name: 'Jane'}, {id: 1, name: 'John'}, {id: 3, name: 'Mike'}];

for (let i = 0; i < arr1.length; i++) {
  for (let j = 0; j < arr2.length; j++) {
    if (arr1[i].id === arr2[j].id && arr1[i].name === arr2[j].name) {
      console.log(`Match found at ${i} in array 1 and ${j} in array 2.`);
      break;
    }
  }
}

方法二：使用Array.prototype.filter()和Array.prototype.some()

可以使用Array.prototype.filter()方法过滤出两个数组中相同的对象，然后使用Array.prototype.some()方法判断是否存在相同的对象。

示例代码：

const arr1 = [{id: 1, name: 'John'}, {id: 2, name: 'Jane'}, {id: 3, name: 'Mike'}];
const arr2 = [{id: 2, name: 'Jane'}, {id: 1, name: 'John'}, {id: 3, name: 'Mike'}];

const matched = arr1.filter(obj1 => arr2.some(obj2 => obj1.id === obj2.id && obj1.name === obj2.name));

console.log(matched);

方法三：使用Array.prototype.reduce()

可以使用Array.prototype.reduce()方法将一个数组转化为一个对象，然后使用Object.keys()和Array.prototype.filter()方法比较两个对象的属性值是否相同。

示例代码：

const arr1 = [{id: 1, name: 'John'}, {id: 2, name: 'Jane'}, {id: 3, name: 'Mike'}];
const arr2 = [{id: 2, name: 'Jane'}, {id: 1, name: 'John'}, {id: 3, name: 'Mike'}];

const obj1 = arr1.reduce((acc, obj) => {
  acc[obj.id] = obj.name;
  return acc;
}, {});

const obj2 = arr2.reduce((acc, obj) => {
  acc[obj.id] = obj.name;
  return acc;
}, {});

const matched = Object.keys(obj1).filter(key => obj1[key] === obj2[key]).map(key => ({id: Number(key), name: obj1[key]}));

console.log(matched);