#include <iostream.h> int max_def(int x, int y) { return (x>y?x:y); } int max_def(int x, int y, int z) { int temp = 0; return (temp=(x>y?x:y))>z?temp:z; } double max_def(double x, double y) { return (x>y?x:y); } int main() { int x1 = 0; int x2 = 0; double d1 = 0.0; double d2 = 0.0; x1 = max_def(5,6); x2 = max_def(2,3,4); d1 = max_def(2. 1,5.6); d2 = max_def(12.3,3.4,7.8);-----------------------------------------------------① cout<<"x1="<<x1<<endl; cout<<"x2="<<x2<<endl; cout<<"d1="<<d1<<endl; cout<<"d2="<<d2<<endl;--------------------------------------------------------② return 1; }

这是一段 C++ 代码，实现了函数重载的例子。函数 max_def() 分别被定义了三次，分别对应了不同的参数类型和个数。

在主函数中，分别调用了四次 max_def() 函数，并将返回值赋给了相应的变量。最后，使用 cout 将四个变量的值输出到控制台上。

需要注意的是，在第①行和第②行之间还有一行代码没有贴出来，可能是因为在复制代码时遗漏了。

相关问题

#include <iostream> #include <vector> #include <algorithm> #include <climits> using namespace std; int getMinTransDelay(int n, vector<vector<int>>& times, int src, int tar) { vector<vector<pair<int, int>>> graph(n + 1); // 构建图 for (auto& time : times) { int u = time[0], v = time[1], w = time[2]; graph[u].push_back({v, w}); } // 初始化距离数组 vector<int> dist(n + 1, INT_MAX); dist[src] = 0; // 初始化待检查节点数组 vector<int> toCheck; toCheck.push_back(src); while (!toCheck.empty()) { bool flag = false; int u = toCheck[0]; // 遍历相邻节点 for (auto& next : graph[u]) { int v = next.first, w = next.second; int newDist = dist[u] + w; // 更新最短距离 if (newDist >= dist[v]) continue; dist[v] = newDist; // 将新节点加入待检查数组 if (find(toCheck.begin(), toCheck.end(), v) == toCheck.end()) { toCheck.push_back(v); flag = true; } } // 移除当前节点并按距离排序 if (!flag) toCheck.erase(toCheck.begin()); else sort(toCheck.begin(), toCheck.end(), [&](int a, int b) { return dist[a] < dist[b]; }); } return dist[tar] == INT_MAX ? -1 : dist[tar]; } int main() { int n, m; vector<vector<int>> times; int src, tar; // 读入数据 cin >> n >> m; for (int i = 0; i < m; i++) { int u, v, w; cin >> u >> v >> w; times.push_back({u, v, w}); } cin >> src >> tar; // 计算最短传输时延 cout << getMinTransDelay(n, times, src, tar) << endl; return 0; } 这段代码用Python怎么写

以下是将上述 C++ 代码转换为 Python 代码的示例：

import sys

def getMinTransDelay(n, times, src, tar):
    graph = [[] for _ in range(n + 1)]

    # 构建图
    for time in times:
        u, v, w = time[0], time[1], time[2]
        graph[u].append((v, w))

    # 初始化距离数组
    dist = [float('inf')] * (n + 1)
    dist[src] = 0

    # 初始化待检查节点数组
    toCheck = [src]

    while toCheck:
        flag = False
        u = toCheck[0]

        # 遍历相邻节点
        for next in graph[u]:
            v, w = next[0], next[1]
            newDist = dist[u] + w

            # 更新最短距离
            if newDist >= dist[v]:
                continue
            dist[v] = newDist

            # 将新节点加入待检查数组
            if v not in toCheck:
                toCheck.append(v)
                flag = True

        # 移除当前节点并按距离排序
        if not flag:
            toCheck.pop(0)
        else:
            toCheck.sort(key=lambda x: dist[x])

    return dist[tar] if dist[tar] != float('inf') else -1

def main():
    n, m = map(int, input().split())
    times = []
    for _ in range(m):
        u, v, w = map(int, input().split())
        times.append([u, v, w])
    src, tar = map(int, input().split())

    # 计算最短传输时延
    print(getMinTransDelay(n, times, src, tar))

if __name__ == "__main__":
    main()

请注意，Python 的语法和一些库函数与 C++ 有所不同，因此在进行转换时需要逐行进行调整。此示例代码应与原始 C++ 代码功能相同。

希望对你有所帮助！如有任何疑问，请随时提问。

#include <iostream> #include <cstring> #include <algorithm> const int MAX_B = 1005; const int MAX_TIMES = 1000005; int arrayB[MAX_B]; int arrayC[MAX_B]; int times[MAX_TIMES]; int dp[MAX_TIMES]; void calculateTimes(int x, int step) { if (x > MAX_B) return; if (times[x] != 1919810 && step >= times[x]) return; if (step < times[x]) times[x] = step; for (int i = 1; i <= x; i++) calculateTimes(x + x / i, step + 1); } int calculateMoney(int n, int k, int b[], int c[], int sum) { int ans = 0; int maxSteps = 0; memset(dp, 0, sizeof dp); for (int i = 1; i <= n; i++) { maxSteps = std::max(maxSteps, times[b[i]]); ans += times[b[i]]; } if (k >= maxSteps * n || k >= ans) { return sum; } for (int i = 1; i <= n; i++) { for (int j = k; j >= times[b[i]]; j--) { dp[j] = std::max(dp[j], dp[j - times[b[i]]] + c[i]); } } return dp[k]; } int main() { for (int i = 1; i < MAX_B; i++) { times[i] = 1919810; } calculateTimes(1, 0); int t; std::scanf("%d", &t); for (int i = 1; i <= t; i++) { int sum = 0; int n, k; std::scanf("%d %d", &n, &k); for (int i = 1; i <= n; i++) { std::scanf("%d", &arrayB[i]); } for (int i = 1; i <= n; i++) { std::scanf("%d", &arrayC[i]); sum += arrayC[i]; } std::printf("%d\n", calculateMoney(n, k, arrayB, arrayC, sum)); } return 0; }

以下是将该代码转换为 Python 语言的版本：

import sys
MAX_B = 1005
MAX_TIMES = 1000005
arrayB = [0] * MAX_B
arrayC = [0] * MAX_B
times = [1919810] * MAX_B
dp = [0] * MAX_TIMES

def calculateTimes(x, step):
    if x > MAX_B:
        return
    if times[x] != 1919810 and step >= times[x]:
        return
    if step < times[x]:
        times[x] = step
    for i in range(1, x+1):
        calculateTimes(x + x // i, step + 1)

def calculateMoney(n, k, b, c, sum):
    ans = 0
    maxSteps = 0
    dp = [0] * MAX_TIMES
    for i in range(1, n+1):
        maxSteps = max(maxSteps, times[b[i]])
        ans += times[b[i]]
    if k >= maxSteps * n or k >= ans:
        return sum
    for i in range(1, n+1):
        for j in range(k, times[b[i]]-1, -1):
            dp[j] = max(dp[j], dp[j - times[b[i]]] + c[i])
    return dp[k]

if __name__ == '__main__':
    for i in range(1, MAX_B):
        times[i] = 1919810
    calculateTimes(1, 0)
    t = int(input())
    for i in range(t):
        sum = 0
        n, k = map(int, input().split())
        arrayB = list(map(int, input().split()))
        arrayC = list(map(int, input().split()))
        sum = sum(arrayC)
        print(calculateMoney(n, k, arrayB, arrayC, sum))