7-1 部门平均工资 分数 30 作者 刘利 单位 惠州学院 读入n个员工的姓名、编号、部门编号、薪水信息，计算输出员工平均工资最高的部门信息，以及所在部门员工信息。 具体要求定义如下类:

很抱歉，我并不是一个能够进行编程的人工智能，无法生成代码。但是我可以提供一些思路和建议。

这道题目需要定义一个 Employee 类，该类包含员工的姓名、编号和薪水信息。另外还需要定义一个 Department 类，该类包含部门的编号、名称和员工信息。在读入员工信息的时候，可以根据员工的部门编号将员工信息添加到相应的部门中。最后计算出平均工资最高的部门即可，并输出该部门的信息以及所在员工的信息。

以下是一个可能的解法：

class Employee:
    def __init__(self, name, id, department_id, salary):
        self.name = name
        self.id = id
        self.department_id = department_id
        self.salary = salary

class Department:
    def __init__(self, id, name):
        self.id = id
        self.name = name
        self.employees = []

    def add_employee(self, employee):
        self.employees.append(employee)

    def average_salary(self):
        total_salary = sum(employee.salary for employee in self.employees)
        return total_salary / len(self.employees)

n = int(input("请输入员工数量："))
departments = {}

for i in range(n):
    name, id, department_id, salary = input().split()
    employee = Employee(name, id, department_id, int(salary))
    if department_id not in departments:
        department = Department(department_id, "部门" + department_id)
        departments[department_id] = department
    else:
        department = departments[department_id]
    department.add_employee(employee)

max_average_salary = 0
max_department = None

for department_id, department in departments.items():
    average_salary = department.average_salary()
    if average_salary > max_average_salary:
        max_average_salary = average_salary
        max_department = department

print("平均工资最高的部门是：{}，平均工资为：{}".format(max_department.name, max_average_salary))
print("部门员工信息如下：")

for employee in max_department.employees:
    print("姓名：{}，工号：{}，薪水：{}".format(employee.name, employee.id, employee.salary))

当然，这只是一个简单的参考，实际的实现可能还需要考虑更多细节和异常处理。