给出一段verilog程序,将8位二进制转换成8位8421BCD
时间: 2023-08-16 12:08:07 浏览: 45
好的,以下是一个将8位二进制转换成8位8421BCD的 Verilog 程序:
```verilog
module bin2bcd(
input [7:0] bin,
output reg [7:0] bcd
);
always @(*) begin
case(bin)
8'b0000_0000: bcd = 8'b0000_0000;
8'b0000_0001: bcd = 8'b0000_0001;
8'b0000_0010: bcd = 8'b0000_0010;
8'b0000_0011: bcd = 8'b0000_0011;
8'b0000_0100: bcd = 8'b0000_0100;
8'b0000_0101: bcd = 8'b0000_0101;
8'b0000_0110: bcd = 8'b0000_0110;
8'b0000_0111: bcd = 8'b0000_0111;
8'b0000_1000: bcd = 8'b0000_1000;
8'b0000_1001: bcd = 8'b0001_0001;
8'b0000_1010: bcd = 8'b0010_0000;
8'b0000_1011: bcd = 8'b0011_0001;
8'b0000_1100: bcd = 8'b0100_0000;
8'b0000_1101: bcd = 8'b0101_0001;
8'b0000_1110: bcd = 8'b0110_0000;
8'b0000_1111: bcd = 8'b0111_0001;
8'b0001_0000: bcd = 8'b1000_0000;
8'b0001_0001: bcd = 8'b1000_0001;
8'b0001_0010: bcd = 8'b1000_0010;
8'b0001_0011: bcd = 8'b1000_0011;
8'b0001_0100: bcd = 8'b1000_0100;
8'b0001_0101: bcd = 8'b1000_0101;
8'b0001_0110: bcd = 8'b1000_0110;
8'b0001_0111: bcd = 8'b1000_0111;
8'b0001_1000: bcd = 8'b1000_1000;
8'b0001_1001: bcd = 8'b1001_0001;
8'b0001_1010: bcd = 8'b1010_0000;
8'b0001_1011: bcd = 8'b1011_0001;
8'b0001_1100: bcd = 8'b1100_0000;
8'b0001_1101: bcd = 8'b1101_0001;
8'b0001_1110: bcd = 8'b1110_0000;
8'b0001_1111: bcd = 8'b1111_0001;
default: bcd = 8'b0000_0000;
endcase
end
endmodule
```
这个模块接受一个 8 位二进制输入 `bin`,并将其转换为 8 位 8421BCD 码输出 `bcd`。使用 `case` 语句实现二进制到 BCD 码的转换,每个 4 位二进制数对应一个 BCD 码。注意要在 `always` 块中使用 `@(*)` 以避免出现潜在的组合逻辑问题。