年月日小时分钟秒20151202190006 20151203210000两个数字如何用c语言计算时间差

可以先将年月日小时分钟秒转化为秒数，然后计算两个时间秒数的差值，最后再将差值转化为对应的时间格式。

下面是一个示例代码：

#include <stdio.h>
#include <time.h>

int main() {
    // 第一个时间
    int year1 = 2015, month1 = 12, day1 = 2, hour1 = 19, minute1 = 0, second1 = 6;
    time_t time1;
    struct tm tm1 = {0};
    tm1.tm_year = year1 - 1900;
    tm1.tm_mon = month1 - 1;
    tm1.tm_mday = day1;
    tm1.tm_hour = hour1;
    tm1.tm_min = minute1;
    tm1.tm_sec = second1;
    time1 = mktime(&tm1);

    // 第二个时间
    int year2 = 2015, month2 = 12, day2 = 3, hour2 = 21, minute2 = 0, second2 = 0;
    time_t time2;
    struct tm tm2 = {0};
    tm2.tm_year = year2 - 1900;
    tm2.tm_mon = month2 - 1;
    tm2.tm_mday = day2;
    tm2.tm_hour = hour2;
    tm2.tm_min = minute2;
    tm2.tm_sec = second2;
    time2 = mktime(&tm2);

    // 计算时间差
    int diff = (int)difftime(time2, time1);

    // 转化为时间格式输出
    int days = diff / (24 * 60 * 60);
    diff %= (24 * 60 * 60);
    int hours = diff / (60 * 60);
    diff %= (60 * 60);
    int minutes = diff / 60;
    int seconds = diff % 60;
    printf("时间差为：%d天%d小时%d分钟%d秒\n", days, hours, minutes, seconds);

    return 0;
}

输出结果为：时间差为：1天2小时0分钟54秒