请举例说明[batch_size,timestep,hidden_size]变换成[timestep,batch_size,hidden_size]的变换过程
时间: 2024-05-03 11:17:28 浏览: 10
假设有一个形状为[3, 4, 2]的张量,其中batch_size为3,timestep为4,hidden_size为2,如下所示:
```
[
[[1, 2], [3, 4], [5, 6], [7, 8]],
[[9, 10], [11, 12], [13, 14], [15, 16]],
[[17, 18], [19, 20], [21, 22], [23, 24]]
]
```
我们需要将其变换为形状为[4, 3, 2]的张量,其中timestep为4,batch_size为3,hidden_size为2,变换过程如下:
1. 将原始张量拆分为3个形状为[4, 2]的矩阵,分别表示每个batch的hidden_state:
```
[
[[1, 2], [3, 4], [5, 6], [7, 8]],
[[9, 10], [11, 12], [13, 14], [15, 16]],
[[17, 18], [19, 20], [21, 22], [23, 24]]
]
->
[
[[1, 2], [3, 4], [5, 6], [7, 8]],
[[9, 10], [11, 12], [13, 14], [15, 16]],
[[17, 18], [19, 20], [21, 22], [23, 24]]
],
[
[[1, 2], [3, 4], [5, 6], [7, 8]],
[[9, 10], [11, 12], [13, 14], [15, 16]],
[[17, 18], [19, 20], [21, 22], [23, 24]]
],
[
[[1, 2], [3, 4], [5, 6], [7, 8]],
[[9, 10], [11, 12], [13, 14], [15, 16]],
[[17, 18], [19, 20], [21, 22], [23, 24]]
]
```
2. 将3个矩阵按照timestep的方向堆叠起来,得到形状为[4, 3, 2]的张量:
```
[
[[1, 2], [3, 4], [5, 6]],
[[7, 8], [9, 10], [11, 12]],
[[13, 14], [15, 16], [17, 18]],
[[19, 20], [21, 22], [23, 24]]
]
```