Error in layout_fun(graph, circular = circular, ...) : 参数没有用(node.positions = list(c(-63.616672, 133.77514, 25.48583, -51.92528, -106.346771, -71.542969, 104.195397, -74.297333, -83.753428, 15.472962, -70.162651, 30.8025, 113.921327, 78.96288, -4.54806, 36.238414, 138.252924, 66.923684, 127.51009, 23.881275, 24.603189, -102.552784, 101.975766, 174.885971, 69.345116, -75.015152, 121.774017, 19.145136, 61.52401, 14.995463, 100.992541, -61.222503, 35.243322, 120.960515, 31.16558, -95.712891, 108.277199, 22.937506, 10.451526, 4.469936, 14.550072, 25.748151, 19.503304, -3.74922, 114.109497, 5.291266, 2.213749, 12.56738, 18.643501, -2.742777, 24.96676, 19.699024, 55.923255, 80.771797, 45.079162, -8.24389, 9.
时间: 2023-09-23 16:09:29 浏览: 227
matlab-grid-on.rar_bar graph_site:www.pudn.com
我很抱歉,我在之前的回答中没有提供完整的代码,导致你遇到了错误。请允许我重新提供一个准确的示例来创建地理布局。
```R
# 安装和加载必要的包
install.packages("ggplot2")
install.packages("sf")
library(ggplot2)
library(sf)
# 创建示例数据
lon <- c(-63.616672, 133.77514, 25.48583, -51.92528, -106.346771, -71.542969)
lat <- c(41.878113, -25.274398, 42.360081, -14.235004, 56.130366, 37.774929)
data <- data.frame(lon, lat)
# 创建地理布局
p <- ggplot() +
geom_sf(data = st_as_sf(data, coords = c("lon", "lat"), crs = 4326)) +
theme_bw() +
labs(title = "Your Map Title") +
xlab("Longitude") +
ylab("Latitude")
# 显示地理布局
print(p)
```
请确保将`lon`和`lat`替换为你自己的节点经纬度坐标。这个示例使用`geom_sf()`函数将经纬度数据转换为`sf`对象,并将其添加到地理布局中。
如果你的问题还有其他方面需要解决,请提供更多的细节,我将尽力帮助你解决问题。
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