lua五子棋对弈三子相连判断

实现三子相连判断可以使用以下方法：

1. 水平方向判断：遍历每一行，如果存在连续三个相同的棋子，则判断游戏结束。

function checkHorizontal(board, row, col, player)
    local count = 0
    for i = col - 2, col do
        if i >= 1 and i + 2 <= 15 and board[row][i] == player and board[row][i+1] == player and board[row][i+2] == player then
            return true
        end
    end
    return false
end

2. 垂直方向判断：遍历每一列，如果存在连续三个相同的棋子，则判断游戏结束。

function checkVertical(board, row, col, player)
    local count = 0
    for i = row - 2, row do
        if i >= 1 and i + 2 <= 15 and board[i][col] == player and board[i+1][col] == player and board[i+2][col] == player then
            return true
        end
    end
    return false
end

3. 左上到右下方向判断：从左上角到右下角的对角线上，如果存在连续三个相同的棋子，则判断游戏结束。

function checkDiagonal1(board, row, col, player)
    local count = 0
    for i = -2, 0 do
        if row + i >= 1 and row + i + 2 <= 15 and col + i >= 1 and col + i + 2 <= 15 and board[row+i][col+i] == player and board[row+i+1][col+i+1] == player and board[row+i+2][col+i+2] == player then
            return true
        end
    end
    return false
end

4. 左下到右上方向判断：从左下角到右上角的对角线上，如果存在连续三个相同的棋子，则判断游戏结束。

function checkDiagonal2(board, row, col, player)
    local count = 0
    for i = -2, 0 do
        if row - i >= 3 and row - i <= 15 and col + i >= 1 and col + i + 2 <= 15 and board[row-i][col+i] == player and board[row-i-1][col+i+1] == player and board[row-i-2][col+i+2] == player then
            return true
        end
    end
    return false
end

将以上四个函数结合起来，可以实现三子相连判断的功能：

function checkWin(board, row, col, player)
    return checkHorizontal(board, row, col, player) or checkVertical(board, row, col, player) or checkDiagonal1(board, row, col, player) or checkDiagonal2(board, row, col, player)
end

在游戏每一步落子后，调用 checkWin 函数判断游戏是否结束。