两个指针矩阵相乘输出结果c++

根据提供的引用内容，没有直接给出两个指针矩阵相乘的代码。但是可以根据引用中的矩阵读入函数和以下代码，实现两个指针矩阵相乘并输出结果：

#include <iostream>
using namespace std;

double** readMatrix(int* rows, int* cols) {
    // 读入矩阵的行数和列数
    scanf("%d %d", rows, cols);
    // 分配内存空间存储矩阵
    double** matrix = (double**)malloc(*rows * sizeof(double*));
    for (int i = 0; i < *rows; i++) {
        matrix[i] = (double*)malloc(*cols * sizeof(double));
    }
    // 读入矩阵的元素
    for (int i = 0; i < *rows; i++) {
        for (int j = 0; j < *cols; j++) {
            scanf("%lf", &matrix[i][j]);        }
    }
    return matrix;
}

void printMatrix(double** matrix, int rows, int cols) {
    for (int i = 0; i < rows; i++) {
        for (int j = 0; j < cols; j++) {
            printf("%lf ", matrix[i][j]);
        }
        printf("\n");
    }
}

int main() {
    int rows1, cols1, rows2, cols2;
    double** matrix1 = readMatrix(&rows1, &cols1);
    double** matrix2 = readMatrix(&rows2, &cols2);

    if (cols1 != rows2) {
        printf("Error: The number of columns in the first matrix must be equal to the number of rows in the second matrix.\n");
        return 0;
    }

    double** result = (double**)malloc(rows1 * sizeof(double*));
    for (int i = 0; i < rows1; i++) {
        result[i] = (double*)malloc(cols2 * sizeof(double));
    }

    for (int i = 0; i < rows1; i++) {
        for (int j = 0; j < cols2; j++) {
            result[i][j] = 0;
            for (int k = 0; k < cols1; k++) {
                result[i][j] += matrix1[i][k] * matrix2[k][j];
            }
        }
    }

    printMatrix(result, rows1, cols2);

    return 0;
}