Error in if (node.number == (Ntip(tree) + 1)) cat("Note: you chose to re-root the tree at it's current root.\n") : the condition has length > 1
时间: 2024-04-15 19:29:43 浏览: 102
非常抱歉,我之前的回答有误。在使用`root`函数时,我们不能同时指定多个基因树的外群。为了解决这个问题,我们需要对基因树文件进行循环处理,并且每次处理一个基因树文件时,都要重新读取物种树。以下是更新后的代码:
```R
library(ape)
library(tools)
# 设置物种树文件路径
species_tree_file <- "species_tree.treefile"
# 设置基因树目录和输出目录
gene_tree_folder <- "/ifs1/User/dengwei/NTF_data/rotted_gene_tree"
output_folder <- "/ifs1/User/dengwei/NTF_data/adj_gene_tree"
# 定义函数:将基因树转化为有根树并保存到输出目录
convert_to_rooted_tree <- function(gene_tree_file, species_tree, output_folder) {
# 读取物种树
species_tree <- read.tree(species_tree)
# 读取基因树
gene_tree <- read.tree(gene_tree_file)
# 设置外群为物种树的根节点
outgroup <- species_tree$root$tip.label
# 定根
rooted_tree <- root(gene_tree, outgroup = outgroup)
# 获取基因树文件名
gene_tree_file_name <- file_path_sans_ext(basename(gene_tree_file))
# 构建输出文件路径
output_file <- file.path(output_folder, paste0(gene_tree_file_name, "_rooted.treefile"))
# 保存有根基因树
write.tree(rooted_tree, file = output_file)
}
# 获取基因树文件列表
gene_tree_files <- list.files(path = gene_tree_folder, pattern = ".treefile", full.names = TRUE)
# 遍历基因树文件并逐个转化为有根基因树
for (gene_tree_file in gene_tree_files) {
convert_to_rooted_tree(gene_tree_file, species_tree_file, output_folder)
}
```
请将`species_tree.treefile`替换为你实际的物种树文件路径。然后,设置基因树目录和输出目录的路径。代码中定义了一个名为`convert_to_rooted_tree`的函数,用于将单个基因树转化为有根基因树,并将其保存到输出目录中。最后,通过遍历基因树文件列表,调用`convert_to_rooted_tree`函数逐个处理基因树文件。请确保你已经安装了ape包和tools包。
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