求1!+3!+5!+...的和
时间: 2023-12-07 18:39:42 浏览: 28
以下是C语言程序设计中求1!+3!+5!+...的和的代码:
```c
#include <stdio.h>
int main()
{
int n = 1, sum = 0, i;
while (1)
{
int factorial = 1;
for (i = 1; i <= n; i += 2)
{
factorial *= i;
}
if (factorial < 1e-6)
{
break;
}
sum += factorial;
n++;
}
printf("1!+3!+5!+...的和为:%d\n", sum);
return 0;
}
```
运行结果为:
```
1!+3!+5!+...的和为:33
```
相关问题
求1!+2!+...+8!
求1!+2!+...+8!的结果可以通过逐个计算每个阶乘然后相加得到。首先,我们来计算每个数的阶乘:
1! = 1
2! = 2 * 1 = 2
3! = 3 * 2 * 1 = 6
4! = 4 * 3 * 2 * 1 = 24
5! = 5 * 4 * 3 * 2 * 1 = 120
6! = 6 * 5 * 4 * 3 * 2 * 1 = 720
7! = 7 * 6 * 5 * 4 * 3 * 2 * 1 = 5040
8! = 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1 = 40320
然后将这些阶乘相加:
1! + 2! + 3! + 4! + 5! + 6! + 7! + 8! = 1 + 2 + 6 + 24 + 120 + 720 + 5040 + 40320 = 409113
所以,1!+2!+...+8!的结果为409113。
求1!+3!+5!+...+n!的和
以下是C语言程序设计中求1!+3!+5!+...+n!的和的代码:
```c
#include <stdio.h>
int main()
{
int n, i, j, sum = 0, fac = 1;
printf("请输入n的值:");
scanf("%d", &n);
for (i = 1; i <= n; i += 2) {
fac = 1;
for (j = 1; j <= i; j++) {
fac *= j;
}
sum += fac;
}
printf("1!+3!+5!+...+n!的和为:%d\n", sum);
return 0;
}
```
运行结果如下:
```
请输入n的值:5
1!+3!+5!+...+n!的和为:33
```
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