shell人机石头剪刀布游戏

在Shell中实现一个简单的石头、剪刀、布游戏可以使用read命令获取用户的输入，然后用if-else语句判断用户的选择是否匹配预设的选项。下面是一个基础的示例：

#!/bin/bash

# 石头、剪刀、布的选项
choices=("rock" "paper" "scissors")

# 输出游戏规则
echo -e "Let's play Rock-Paper-Scissors!\n"
echo "Type 'rock', 'paper', or 'scissors'."

# 读取用户输入
while true; do
  read -p "Your choice: " user_choice
  if [[ "$user_choice" =~ ^(rock|paper|scissors)$ ]]; then
    break
  else
    echo "Invalid input! Please try again."
  fi
done

# 随机选择电脑的选择
computer_choice=$((RANDOM % 3 + 1))
case $computer_choice in
  1) computer_choice="rock";;
  2) computer_choice="paper";;
  3) computer_choice="scissors";;
esac

# 比较双方的选择并输出结果
echo "Computer chose: $computer_choice"

if [ "$user_choice" == "$computer_choice" ]; then
  echo "It's a tie!"
elif [ "$user_choice" = "rock" ] && [ "$computer_choice" = "scissors" ]; then
  echo "You win!"
elif [ "$user_choice" = "paper" ] && [ "$computer_choice" = "rock" ]; then
  echo "You win!"
elif [ "$user_choice" = "scissors" ] && [ "$computer_choice" = "paper" ]; then
  echo "You win!"
else
  echo "Computer wins!"
fi

# 游戏结束提示
echo "Game over!"

每次运行这个脚本，你会看到游戏流程和最终的结果。