python二维数组回形遍历

以下是Python实现二维数组回形遍历的代码示例：

def spiralOrder(matrix):
    if not matrix:
        return []
    m, n = len(matrix), len(matrix[0])
    left, right, top, bottom = 0, n - 1, 0, m - 1
    res = []
    while left <= right and top <= bottom:
        for i in range(left, right + 1):
 res.append(matrix[top][i])
        top += 1
        for i in range(top, bottom + 1):
            res.append(matrix[i][right])
        right -= 1
        if top <= bottom:
            for i in range(right, left - 1, -1):
                res.append(matrix[bottom][i])
            bottom -= 1
        if left <= right:
            for i in range(bottom, top - 1, -1):
                res.append(matrix[i][left])
            left += 1
    return res

matrix = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
result = spiralOrder(matrix)
print(result)  # 输出：[1, 2, 3, 6, 9, 8, 7, 4, 5]