qt用dijkstra邻接链表算最短路径
时间: 2023-09-15 12:23:04 浏览: 83
以下是Qt中使用邻接链表实现Dijkstra算法求解最短路径的示例代码:
```c++
#include <QtDebug>
#include <QVector>
#include <QMap>
//定义邻接链表中的结点
struct Node {
int index;
int weight;
Node(int idx, int wgt): index(idx), weight(wgt) {}
};
//定义邻接链表
typedef QVector<Node> AdjList;
typedef QMap<int, AdjList> Graph;
//Dijkstra算法求解最短路径
void dijkstra(const Graph& graph, int start, QVector<int>& dist, QVector<int>& prev) {
int n = graph.size();
QVector<bool> visited(n, false);
dist.fill(INT_MAX, n);
dist[start] = 0;
prev.fill(-1, n);
for (int i = 0; i < n; i++) {
int u = -1;
for (int j = 0; j < n; j++) {
if (!visited[j] && (u == -1 || dist[j] < dist[u])) {
u = j;
}
}
if (dist[u] == INT_MAX) break;
visited[u] = true;
const AdjList& adj = graph[u];
for (int j = 0; j < adj.size(); j++) {
int v = adj[j].index;
int w = adj[j].weight;
if (dist[u] + w < dist[v]) {
dist[v] = dist[u] + w;
prev[v] = u;
}
}
}
}
int main() {
Graph graph;
graph[0] = AdjList() << Node(1, 2) << Node(2, 5) << Node(3, 1);
graph[1] = AdjList() << Node(0, 2) << Node(2, 3) << Node(4, 1);
graph[2] = AdjList() << Node(0, 5) << Node(1, 3) << Node(3, 2) << Node(4, 5);
graph[3] = AdjList() << Node(0, 1) << Node(2, 2) << Node(4, 4);
graph[4] = AdjList() << Node(1, 1) << Node(2, 5) << Node(3, 4);
QVector<int> dist(graph.size());
QVector<int> prev(graph.size());
dijkstra(graph, 0, dist, prev);
qDebug() << "Shortest path from 0 to 4:";
for (int i = 4; i != -1; i = prev[i]) {
qDebug() << i;
}
qDebug() << "Shortest distance: " << dist[4];
return 0;
}
```
在这个示例中,我们定义了邻接链表的结构体`Node`和类型别名`AdjList`和`Graph`。然后,我们实现了Dijkstra算法的函数`dijkstra`,该函数接受一个邻接链表和一个起点,并计算出从起点到每个顶点的最短距离和最短路径。
最后,我们在`main`函数中创建了一个邻接链表,调用了`dijkstra`函数来计算最短路径和距离,并打印结果。
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