我有以下postgres数据库的SQL语句:select roadcode,roadname,roadstart,roadends,f044 from gpsxd WHERE roadcode in ('X020360902') ORDER BY roadcode,roadstart ,此语句查询出的结果是每条路线的最小分段,如下数据 roadcode roadname roadstart roadends f044 X020360902 湾里-沙江 0 2.987 11101360902 X020360902 湾里-沙江 2.987 3.42 11101360902 X020360902 湾里-沙江 3.42 5.109 11101360902 X020360902 湾里-沙江 5.109 8.157 11101360902 X020360902 湾里-沙江 8.157 8.326 11101360521 X020360902 湾里-沙江 8.326 8.926 11101360902 ,现需求对结果进行分组,重组的要求是将按roadcode和f044分组,其中分组结果里的roadends和roadstart 相同时视为连续的路段,比如分组后的路线编码X020360902 结果数据应该是如下 roadcode roadname roadstart roadends f044 X020360902 湾里-沙江 0 8.157 11101360902 X020360902 湾里-沙江 8.157 8.326 11101360521 X020360902 湾里-沙江 8.326 8.926 11101360902 最终生成一个函数
时间: 2024-03-13 22:45:23 浏览: 47
以下是一个 PostgreSQL 函数,可以实现你所需的结果:
```
CREATE OR REPLACE FUNCTION group_road_segments()
RETURNS TABLE (roadcode text, roadname text, roadstart numeric, roadends numeric, f044 text) AS
$$
DECLARE
result record;
last_roadcode text := '';
last_f044 text := '';
last_roadstart numeric := 0;
last_roadends numeric := 0;
BEGIN
FOR result IN SELECT roadcode, roadname, roadstart, roadends, f044 FROM gpsxd WHERE roadcode IN ('X020360902') ORDER BY roadcode, roadstart LOOP
IF result.roadcode <> last_roadcode OR result.f044 <> last_f044 OR result.roadstart <> last_roadends THEN
IF last_roadcode <> '' THEN
RETURN NEXT (last_roadcode, result.roadname, last_roadstart, last_roadends, last_f044);
END IF;
last_roadcode := result.roadcode;
last_f044 := result.f044;
last_roadstart := result.roadstart;
END IF;
last_roadends := result.roadends;
END LOOP;
IF last_roadcode <> '' THEN
RETURN NEXT (last_roadcode, result.roadname, last_roadstart, last_roadends, last_f044);
END IF;
END;
$$ LANGUAGE plpgsql;
```
该函数返回一个表,其中包含按 roadcode 和 f044 分组的结果,其中相邻的路段将被组合成单个路段。你可以将 'X020360902' 替换为其他 roadcode 值以查询不同的数据。请注意,该函数假定数据已按 roadcode 和 roadstart 排序。
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