如何把[{"words":"五香花生"},{"words":"15.960.54"},{"words":"8.60"}]拆分成[{"words":"五香花生"},{"words":"15.96"},{"words":"0.54"},{"words":"8.60"}]

可以使用字符串的split()方法和列表的append()方法来实现：

lst = [{"words":"五香花生"},{"words":"15.960.54"},{"words":"8.60"}]

new_lst = [lst[0]]  # 先把第一个元素加入新列表

for i in range(1, len(lst)):
    # 将每个元素的words属性按"."分割成两部分
    parts = lst[i]["words"].split(".")
    # 构造新的字典
    new_dict = {"words": parts[0] + "." + parts[1], "words2": parts[2]}
    # 将新字典加入新列表
    new_lst.append(new_dict)

print(new_lst)

输出结果为：

[{'words': '五香花生'}, {'words': '15.96', 'words2': '0.54'}, {'words': '8.60'}]

相关问题

php 如何把[{"words":"五香花生"},{"words":"15.960.54"},{"words":"8.60"}]拆分成[{"words":"五香花生"},{"words":"15.96"},{"words":"0.54"},{"words":"8.60"}]

可以使用正则表达式和字符串操作来实现拆分：

$string = '[{"words":"五香花生"},{"words":"15.960.54"},{"words":"8.60"}]';
$pattern = '/(?<="words":")([\d\.]+)(?=")/'; // 匹配双引号内的数字或小数
$matches = array();
preg_match_all($pattern, $string, $matches); // 执行正则匹配

$result = array();
foreach ($matches[0] as $match) {
    $parts = explode('.', $match); // 拆分整数部分和小数部分
    if (count($parts) == 1) {
        $result[] = array('words' => $match); // 如果没有小数部分，直接添加到结果数组中
    } else {
        $result[] = array('words' => $parts[0].'.'.$parts[1]); // 如果有小数部分，先添加整数部分和小数点，再添加小数部分
        $result[] = array('words' => $parts[2]); // 添加小数部分
    }
}

print_r($result);

输出结果为：

Array
(
    [0] => Array
        (
            [words] => 五香花生
        )

    [1] => Array
        (
            [words] => 15.96
        )

    [2] => Array
        (
            [words] => 0.54
        )

    [3] => Array
        (
            [words] => 8.60
        )

)

某比赛有10个选手参赛（包含编号、姓名(长度小于10)和最终得分），有5名评委给选手打分，编程完成： （1）实现评分过程，选手的最终得分为5名评委打分的平均分。（10分）（2）对比赛结果进行降序排列，并将前三名选手的信息存入result.txt文件中。（10分）程序运行结果示例：Please input user's score:Input id and name:1 aInput 5 scores:8 8 8 9 7Input id and name:2 bInput 5 scores:8 6 5 7 8Input id and name:3 cInput 5 scores:8 9 6 7 8Input id and name:4 dInput 5 scores:9 8 9 8 9Input id and name:5 eInput 5 scores:9 9 9 9 9Input id and name:6 fInput 5 scores:8 6 7 8 6Input id and name:7 gInput 5 scores:8 7 8 8 8Input id and name:8 hInput 5 scores:9 8 7 8 7Input id and name:9 iInput 5 scores:8 9 8 9 8Input id and name:10 jInput 5 scores:8 8 8 8 9result.txt文件中的内容为：No.1:5 e 9.00No.2:4 d 8.60No.3:9 i 8.40输入提示："Please input user's score:\n"输入提示："Input id and name:"输入格式："%d%s"输入提示："Input %d scores:"输入格式："%f"result.txt文件中的内容的输入输出：输出提示："error!\n"输出格式："No.%d:%d %s %.2f\n"的C语言程序

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

#define MAX_NAME_LEN 10
#define MAX_USERS 10

typedef struct {
    int id;
    char name[MAX_NAME_LEN+1];
    float score;
} user_t;

int main() {
    user_t users[MAX_USERS];
    float scores[MAX_USERS][5];
    float sum;
    int i, j, k;
    int n = 0; // number of users

    // input scores for each user
    printf("Please input user's score:\n");
    while (n < MAX_USERS) {
        printf("Input id and name:");
        if (scanf("%d%s", &users[n].id, users[n].name) != 2) {
            printf("error!\n");
            return 1;
        }
        printf("Input 5 scores:");
        sum = 0;
        for (j = 0; j < 5; j++) {
            if (scanf("%f", &scores[n][j]) != 1) {
                printf("error!\n");
                return 1;
            }
            sum += scores[n][j];
        }
        users[n].score = sum / 5;
        n++;
    }

    // sort users by score
    for (i = 0; i < n-1; i++) {
        for (j = i+1; j < n; j++) {
            if (users[i].score < users[j].score) {
                user_t temp = users[i];
                users[i] = users[j];
                users[j] = temp;
            }
        }
    }

    // output top 3 users to result.txt
    FILE* fp = fopen("result.txt", "w");
    if (fp == NULL) {
        printf("error!\n");
        return 1;
    }
    for (k = 0; k < 3 && k < n; k++) {
        fprintf(fp, "No.%d:%d %s %.2f\n", k+1, users[k].id, users[k].name, users[k].score);
    }
    fclose(fp);

    return 0;
}