设计一个python程序,可以通过输入一个需要达到的最终分数,输出最优的底层kpi各值
时间: 2024-04-07 15:33:17 浏览: 15
以下是一个设计的示例程序,它可以帮助您通过输入最终需要达到的分数来输出最优的底层KPI值:
```python
def adjust_kpi(target_score):
# 定义初始的底层KPI值
kpi1 = 50
kpi2 = 50
kpi3 = 50
# 定义初始的分支板块权重和能力权重
branch_weights = [0.2, 0.3, 0.5]
ability_weights = [0.05, 0.1, 0.15, 0.3, 0.4]
# 定义迭代次数和学习率
iterations = 1000
learning_rate = 0.01
# 进行迭代调整
for _ in range(iterations):
# 根据当前的底层KPI值计算得分
current_score = calculate_score(kpi1, kpi2, kpi3, branch_weights, ability_weights)
# 计算与目标得分之间的差距
diff = target_score - current_score
# 根据差距和学习率调整底层KPI值
kpi1 += learning_rate * diff * branch_weights[0] * ability_weights[0]
kpi2 += learning_rate * diff * branch_weights[0] * ability_weights[1]
kpi3 += learning_rate * diff * branch_weights[0] * ability_weights[2]
# 防止超出取值范围
kpi1 = max(0, min(100, kpi1))
kpi2 = max(0, min(100, kpi2))
kpi3 = max(0, min(100, kpi3))
# 返回最优的底层KPI值
return kpi1, kpi2, kpi3
def calculate_score(kpi1, kpi2, kpi3, branch_weights, ability_weights):
# 根据底层KPI值和权重计算得分
branch_scores = [kpi1, kpi2, kpi3]
ability_scores = [kpi1, kpi2, kpi3, kpi1, kpi2]
branch_score = sum(score * weight for score, weight in zip(branch_scores, branch_weights))
ability_score = sum(score * weight for score, weight in zip(ability_scores, ability_weights))
return branch_score + ability_score
# 输入目标分数
target_score = float(input("请输入目标分数:"))
# 调用函数获取最优的底层KPI各值
kpi1, kpi2, kpi3 = adjust_kpi(target_score)
# 输出最优的底层KPI各值
print("最优的底层KPI各值:")
print("KPI1:", kpi1)
print("KPI2:", kpi2)
print("KPI3:", kpi3)
```
请注意,这只是一个示例程序,具体实现可能需要根据您的需求进行调整。此外,因为缺少具体的计算公式和数据,上述示例中的计算方式仅供参考,您可能需要根据实际情况进行修改。