动态规划算法求解0/1背包问题代码（关键行注释）python

好的，我可以提供一个简单的0/1背包问题的动态规划算法代码示例，关键行做了注释。注意，这里给出的是一维数组的实现方法：

def knapsack01_dp(capacity, weight, value):
    """
    Uses dynamic programming to solve the 0/1 knapsack problem.
    
    Args:
        capacity (int): maximum capacity of the knapsack
        weight (list[int]): list of weights of the items
        value (list[int]): list of values of the items
    
    Returns:
        int: maximum value that can be achieved with the given capacity and items
    """
    n = len(weight)
    dp = [0] * (capacity + 1)
    for i in range(n):
        for j in range(capacity, 0, -1):
            if j >= weight[i]:
                dp[j] = max(dp[j], dp[j - weight[i]] + value[i])   # 关键行：动态更新dp数组
    return dp[capacity]

希望这个代码能够帮到您！如果您有更多问题，请继续提出。