写一段代码，需求是贪吃蛇

贪吃蛇是一个经典的电子游戏，通常由一个控制蛇移动、吃到食物增长的游戏界面组成。由于这是一个涉及图形用户界面和游戏逻辑的复杂程序，下面提供一个简化的Python版文本贪吃蛇游戏的基本代码框架：

import curses
import random

# 初始化屏幕
stdscr = curses.initscr()
curses.curs_set(0)  # 隐藏光标

# 设置窗口大小
win = curses.newwin(curses.LINES, curses.COLS, 0, 0)

# 蛇的位置和方向
snake = [[1, curses.LINES // 2], [0, curses.LINES // 2 - 1]]
direction = 'right'

# 食物的位置
food = [random.randint(1, curses.COLS - 2), random.randint(1, curses.LINES - 2)]

while True:
    win.clear()
    
    for pos in snake[:-1]:
        win.addch(pos[0], pos[1], ' ')
    win.addch(snake[-1][0], snake[-1][1], 'O')  # 蛇头
    win.addch(food[0], food[1], '*')  # 食物
    
    if direction == 'right':
        snake.insert(0, [snake[0][0] + 1, snake[0][1]])
    elif direction == 'left':
        snake.insert(0, [snake[0][0] - 1, snake[0][1]])
    elif direction == 'up':
        snake.insert(0, [snake[0][0], snake[0][1] - 1])
    else:  # down
        snake.insert(0, [snake[0][0], snake[0][1] + 1])

    if snake[0] == food or (snake[0][0] < 1 or snake[0][0] > curses.COLS - 2 or snake[0][1] < 1 or snake[0][1] > curses.LINES - 2):
        print("Game over!")
        break

    # 检查碰撞
    for i in range(1, len(snake)):
        if snake[i] == snake[0]:
            print("Game over!")
            break

    keypress = stdscr.getch()
    if keypress == ord('a'):
        direction = 'left'
    elif keypress == ord('d'):
        direction = 'right'
    elif keypress == ord('w'):
        direction = 'up'
    elif keypress == ord('s'):
        direction = 'down'

    if snake[0] == food:
        food = [random.randint(1, curses.COLS - 2), random.randint(1, curses.LINES - 2)]
        snake.append([0, 0])  # 增加长度

stdscr.refresh()
curses.endwin()