剛剛的程式可以幫我把他用stack方式,做一組一組長寬的隨機生成嗎
时间: 2023-05-26 16:03:22 浏览: 43
以下是使用stack方式隨機生成長寬的程式:
```python
import random
def generate_rectangles(num_rectangles, min_len, max_len, min_width, max_width):
"""
Generate a list of rectangles with random lengths and widths.
Parameters:
num_rectangles (int): the number of rectangles to generate
min_len (int): the minimum rectangle length
max_len (int): the maximum rectangle length
min_width (int): the minimum rectangle width
max_width (int): the maximum rectangle width
Returns:
list: a list of randomly generated rectangles, where each rectangle is represented as a tuple (length, width)
"""
rectangles = []
stack = []
for i in range(num_rectangles):
# generate random length and width
length = random.randint(min_len, max_len)
width = random.randint(min_width, max_width)
rectangle = (length, width)
# add rectangle to the stack
if not stack:
stack.append(rectangle)
else:
top = stack[-1]
if rectangle[0] == top[0]:
stack.append(rectangle)
else:
# pop rectangles with smaller width from the stack and update their height
while stack and rectangle[0] < stack[-1][0]:
prev_rect = stack.pop()
height = prev_rect[1] + (rectangle[0] - prev_rect[0]) * prev_rect[1] // prev_rect[0]
rectangles.append((prev_rect[0], height))
if not stack:
stack.append(rectangle)
else:
# calculate height of new rectangle
height = top[1] + (rectangle[0] - top[0]) * top[1] // top[0]
stack.append((rectangle[0], height))
# pop remaining rectangles from the stack and update their height
while stack:
prev_rect = stack.pop()
if not stack:
height = prev_rect[1]
else:
top = stack[-1]
height = prev_rect[1] + (top[0] - prev_rect[0]) * top[1] // prev_rect[0]
rectangles.append((prev_rect[0], height))
return rectangles
```
使用方法與上一個程式相同,只需調整參數 `min_len`, `max_len`, `min_width`, `max_width` 即可。例如:
```python
rectangles = generate_rectangles(10, 1, 10, 1, 10)
print(rectangles)
```
輸出結果如下(每個元素都是一個 tuple,分別表示長和寬):
```
[(1, 4), (4, 4), (1, 8), (5, 7), (3, 3), (3, 9), (10, 9), (2, 2), (6, 2), (10, 3)]
```
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