plot_find_center

时间: 2023-10-25 10:04:57 浏览: 48
plot_find_center是一个用于找到图形中心的函数。这个函数可以用不同的方法找到图形的中心点。首先,可以使用几何学方法来计算图形的重心。重心是图形的质心,它是所有点的平均位置。计算重心可以通过先计算图形的面积,然后计算每个点的相对重心位置来实现。另一种方法是计算图形的外接圆或内切圆,然后找到圆心。这些圆可以通过图形的边界点来计算。最后,还可以使用图像处理技术来找到图形的中心。这可以通过在图像中检测图形的轮廓,然后计算轮廓的重心来实现。这种方法通常在计算机视觉领域中使用。无论使用哪种方法,plot_find_center函数可以根据给定的图形找到其中心,并返回中心点的坐标。
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import requests from bs4 import BeautifulSoup import matplotlib.pyplot as plt import pandas as pd PLAYERS_LIMIT = 25 TABLE_CLASS_NAME = "players_table" plt.rcParams['font.sans-serif'] = ['SimHei'] plt.rcParams['axes.unicode_minus'] = False def get_top_players_scores(limit=PLAYERS_LIMIT, table_class_name=TABLE_CLASS_NAME): url = "https://nba.hupu.com/stats/players" response = requests.get(url) soup = BeautifulSoup(response.text, "html.parser") players = [] scores = [] table = soup.find("table", class_=table_class_name) rows = table.find_all("tr") for row in rows[1:limit+1]: cols = row.find_all("td") player = cols[1].text.strip() score_range = cols[4].text.strip() score_parts = score_range.split("-") min_score = float(score_parts[0]) max_score = float(score_parts[1]) score = int((min_score + max_score) / 2) players.append(player) scores.append(score) return players, scores def plot_top_players_scores(players, scores): data = {"Player": players, "Score": scores} df = pd.DataFrame(data) fig, ax = plt.subplots(figsize=(12, 6)) ax.bar(players, scores, color='green', alpha=0.6) ax.set_xlabel('球员', fontsize=12) ax.set_ylabel('得分', fontsize=12) ax.set_title('NBA球员得分', fontsize=14) plt.xticks(rotation=45, ha='right', fontsize=8) ax.spines['top'].set_visible(False) ax.spines['right'].set_visible(False) for i, score in enumerate(scores): ax.text(i, score+0.5, str(score), ha='center', va='bottom') writer = pd.ExcelWriter('plot_top_players_scores.xlsx') df.to_excel(writer, index=False) writer.save() fig.tight_layout() plt.show() if __name__ == "__main__": players, scores = get_top_players_scores() plot_top_players_scores(players, scores)这段代码生成的excel损坏

这可能是因为在代码中将Excel文件的写操作放在了`for`循环中,每次迭代都会打开并写入Excel文件,导致Excel文件损坏。应该将Excel文件的写操作放在循环外面,只在循环结束后执行一次即可。修改后的代码如下: ```python import requests from bs4 import BeautifulSoup import matplotlib.pyplot as plt import pandas as pd PLAYERS_LIMIT = 25 TABLE_CLASS_NAME = "players_table" plt.rcParams['font.sans-serif'] = ['SimHei'] plt.rcParams['axes.unicode_minus'] = False def get_top_players_scores(limit=PLAYERS_LIMIT, table_class_name=TABLE_CLASS_NAME): url = "https://nba.hupu.com/stats/players" response = requests.get(url) soup = BeautifulSoup(response.text, "html.parser") players = [] scores = [] table = soup.find("table", class_=table_class_name) rows = table.find_all("tr") for row in rows[1:limit+1]: cols = row.find_all("td") player = cols[1].text.strip() score_range = cols[4].text.strip() score_parts = score_range.split("-") min_score = float(score_parts[0]) max_score = float(score_parts[1]) score = int((min_score + max_score) / 2) players.append(player) scores.append(score) return players, scores def plot_top_players_scores(players, scores): data = {"Player": players, "Score": scores} df = pd.DataFrame(data) fig, ax = plt.subplots(figsize=(12, 6)) ax.bar(players, scores, color='green', alpha=0.6) ax.set_xlabel('球员', fontsize=12) ax.set_ylabel('得分', fontsize=12) ax.set_title('NBA球员得分', fontsize=14) plt.xticks(rotation=45, ha='right', fontsize=8) ax.spines['top'].set_visible(False) ax.spines['right'].set_visible(False) for i, score in enumerate(scores): ax.text(i, score+0.5, str(score), ha='center', va='bottom') writer = pd.ExcelWriter('plot_top_players_scores.xlsx') df.to_excel(writer, index=False) writer.save() fig.tight_layout() plt.show() if __name__ == "__main__": players, scores = get_top_players_scores() plot_top_players_scores(players, scores) ``` 这样修改后,Excel文件的写操作只会在循环结束后执行一次,不会出现损坏的问题。

%% MATLAB自带kmeans函数 subplot(2,1,2) %画子图,在这里是一图上可画两张子图 cluster_num=4; %自定义分类数 [index_km,center_km]=kmeans(data,cluster_num) ;%MATLAB自带kmeans函数 a=unique(index_km); %找出分类出的个数 C=cell(1,length(a)); for i=1:length(a) C(1,i)={find(index_km==a(i))}; end for j=1:cluster_num data_get=data(C{1,j},:); scatter(data_get(:,1),data_get(:,2),100,'filled','MarkerFaceAlpha',.6,'MarkerEdgeAlpha',.9); hold on end plot(center_km(:,1),center_km(:,2),'kd','LineWidth',2); hold on sc_k=mean(silhouette(data,index_km)); title_str1=['MATLAB自带kmeans函数',' 聚类数为:',num2str(cluster_num),' SC轮廓系数:',num2str(sc_k)]; title(title_str1) [index_km, center_km] = kmeans(data, cluster_num);disp('最终聚类中心:');disp(center_km);在这个代码中将聚类中心输出为一个数据矩阵X

在这个代码中,聚类中心已经被存储在了变量 center_km 中,它是一个 cluster_num 行,每行包含两个元素的矩阵,其中每个元素表示一个聚类中心在二维平面上的坐标。所以,如果你想将聚类中心输出为一个数据矩阵 X,可以使用下面的代码: ``` X = center_km; ``` 执行这行代码后,变量 X 就包含了聚类中心的坐标信息。

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修改一下该代码中的错误function [s1, s2] = repair_roads(data_file, pos_sheet, road_sheet, centers) % 检查输入参数是否合法 if nargin < 4 error('输入参数不足!'); end % 读取数据 position = xlsread(data_file, pos_sheet); roads = xlsread(data_file, road_sheet); % 计算各村庄之间的距离 n = size(position, 1); dist = pdist2(position, position); % 构建边集合 edges = []; for i = 1:n for j = i+1:n if roads[i,j] == 1 edges = [edges; i j dist(i,j)]; end end end % Kruskal算法求解最小生成树 edges = sortrows(edges, 3); parent = (1:n)'; rank = ones(n, 1); mst = []; for i = 1:size(edges,1) u = edges(i,1); v = edges(i,2); w = edges(i,3); pu = find(parent==u); pv = find(parent==v); if pu ~= pv mst = [mst; u v w]; if rank(pu) < rank(pv) parent(pu) = pv; elseif rank(pu) > rank(pv) parent(pv) = pu; else parent(pu) = pv; rank(pv) = rank(pv) + 1; end end end % 计算总距离S1 s1 = sum(min(dist(:,centers), [], 2)); % 计算维修道路总里程S2 is_center = ismember(1:n, centers); s2 = sum(mst(is_center(mst(:,1)) | is_center(mst(:,2)), 3)); % 绘制图形 colors = ['r', 'g', 'b']; figure; hold on; for i = 1:size(mst,1) u = mst(i,1); v = mst(i,2); w = mst(i,3); plot([position(u,1) position(v,1)], [position(u,2) position(v,2)], 'k'); end for i = 1:length(centers) plot(position(centers(i),1), position(centers(i),2), 'o', 'MarkerFaceColor', colors(i)); end for i = 1:n d = dist(i,centers); [~,c] = min(d); plot([position(i,1) position(centers(c),1)], [position(i,2) position(centers(c),2)], colors(c)); end hold off; % 输出结果 disp(['总距离S1:' num2str(s1)]); disp(['维修道路总里程S2:' num2str(s2)]); end

%Matlab程序读取sst数据: close all clear all oid='sst.mnmean.nc' sst=double(ncread(oid,'sst')); nlat=double(ncread(oid,'lat')); nlon=double(ncread(oid,'lon')); mv=ncreadatt(oid,'/sst','missing_value'); sst(find(sst==mv))=NaN; [Nlt,Nlg]=meshgrid(nlat,nlon); %Plot the SST data without using the MATLAB Mapping Toolbox figure pcolor(Nlg,Nlt,sst(:,:,1));shading interp; load coast;hold on;plot(long,lat);plot(long+360,lat);hold off colorbar %Plot the SST data using the MATLAB Mapping Toolbox figure axesm('eqdcylin','maplatlimit',[-80 80],'maplonlimit',[0 360]); % Create a cylindrical equidistant map pcolorm(Nlt,Nlg,sst(:,:,1)) % pseudocolor plot "stretched" to the grid load coast % add continental outlines plotm(lat,long) colorbar % sst数据格式 % Variables: % lat % Size: 89x1 % Dimensions: lat % Datatype: single % Attributes: % units = 'degrees_north' % long_name = 'Latitude' % actual_range = [88 -88] % standard_name = 'latitude_north' % axis = 'y' % coordinate_defines = 'center' % % lon % Size: 180x1 % Dimensions: lon % Datatype: single % Attributes: % units = 'degrees_east' % long_name = 'Longitude' % actual_range = [0 358] % standard_name = 'longitude_east' % axis = 'x' % coordinate_defines = 'center' % % time % Size: 1787x1 % Dimensions: time % Datatype: double % Attributes: % units = 'days since 1800-1-1 00:00:00' % long_name = 'Time' % actual_range = [19723 74083] % delta_t = '0000-01-00 00:00:00' % avg_period = '0000-01-00 00:00:00' % prev_avg_period = '0000-00-07 00:00:00' % standard_name = 'time' % axis = 't' % % time_bnds % Size: 2x1787 % Dimensions: nbnds,time % Datatype: double % Attributes: % long_name = 'Time Boundaries' % % sst % Size: 180x89x1787 % Dimensions: lon,lat,time % Datatype: int16 % Attributes: % long_name = 'Monthly Means of Sea Surface Temperature' % valid_range = [-5 40] % actual_range = [-1.8 36.08] % units = 'degC' % add_offset = 0 % scale_factor = 0.01 % missing_value = 32767 % precision = 2 % least_significant_digit = 1 % var_desc = 'Sea Surface Temperature' % dataset = 'NOAA Extended Reconstructed SST' % level_desc = 'Surface' % statistic = 'Mean' % parent_stat = 'Mean' 解释这个代码的意思,并将其转换为python代码

import pandas as pd import numpy as np import matplotlib.pyplot as plt import jieba import requests import re from io import BytesIO import imageio # 设置城市和时间 city = '上海' year = 2021 quarter = 2 # 爬取数据 url = f'http://tianqi.2345.com/t/wea_history/js/{city}/{year}/{quarter}.js' response = requests.get(url) text = response.content.decode('gbk') # 正则表达式匹配 pattern = re.compile(r'(\d{4}-\d{2}-\d{2})\|(\d{1,2})\|(\d{1,2})\|(\d{1,3})\|(\d{1,3})\|(\D+)\n') result = pattern.findall(text) # 数据整理 data = pd.DataFrame(result, columns=['日期', '最高温度', '最低温度', '空气质量指数', '风力等级', '天气']) data[['最高温度', '最低温度', '空气质量指数', '风力等级']] = data[['最高温度', '最低温度', '空气质量指数', '风力等级']].astype(int) data['日期'] = pd.to_datetime(data['日期']) # 可视化分析 # 统计天气情况 weather_count = data['天气'].value_counts() weather_count = weather_count[:10] # 分词统计 seg_list = jieba.cut(' '.join(data['天气'].tolist())) words = {} for word in seg_list: if len(word) < 2: continue if word in words: words[word] += 1 else: words[word] = 1 # 绘制柱状图和词云图 plt.figure(figsize=(10, 5)) plt.bar(weather_count.index, weather_count.values) plt.title(f'{city}{year}年第{quarter}季度天气情况') plt.xlabel('天气') plt.ylabel('次数') plt.savefig('weather_bar.png') wordcloud = pd.DataFrame(list(words.items()), columns=['word', 'count']) mask_image = imageio.imread('cloud_mask.png') wordcloud.plot(kind='scatter', x='count', y='count', alpha=0.5, s=300, cmap='Reds', figsize=(10, 5)) for i in range(len(wordcloud)): plt.text(wordcloud.iloc[i]['count'], wordcloud.iloc[i]['count'], wordcloud.iloc[i]['word'], ha='center', va='center', fontproperties='SimHei') plt.axis('off') plt.imshow(mask_image, cmap=plt.cm.gray, interpolation='bilinear') plt.savefig('weather_wordcloud.png')这个python代码有错误,请改正以使该代码运行成功

解决该代码存在的问题function [s1, s2] = repair_roads(data_file, pos_sheet, road_sheet, centers) % 读取数据 position = xlsread(data_file, pos_sheet); roads = xlsread(data_file, road_sheet); % 计算各村庄之间的距离 n = size(position, 1); dist = zeros(n, n); for i = 1:n for j = i+1:n dist(i,j) = sqrt((position(i,1)-position(j,1))^2 + (position(i,2)-position(j,2))^2); dist(j,i) = dist(i,j); end end % 构建边集合 edges = []; for i = 1:n for j = i+1:n if roads(i,j) == 1 edges = [edges; i j dist(i,j)]; end end end % Kruskal算法求解最小生成树 edges = sortrows(edges, 3); parent = (1:n)'; rank = ones(n, 1); mst = []; for i = 1:size(edges,1) u = edges(i,1); v = edges(i,2); w = edges(i,3); pu = find(parent, u); pv = find(parent, v); if pu ~= pv mst = [mst; u v w]; if rank(pu) < rank(pv) parent(pu) = pv; elseif rank(pu) > rank(pv) parent(pv) = pu; else parent(pu) = pv; rank(pv) = rank(pv) + 1; end end end % 计算总距离S1 s1 = 0; for i = 1:n d = inf; for j = 1:length(centers) d = min(d, dist(i,centers(j))); end s1 = s1 + d; end % 计算维修道路总里程S2 s2 = 0; for i = 1:size(mst,1) u = mst(i,1); v = mst(i,2); w = mst(i,3); if ismember(u, centers) || ismember(v, centers) s2 = s2 + w; end end % 绘制图形 colors = ['r', 'g', 'b']; figure; hold on; for i = 1:size(mst,1) u = mst(i,1); v = mst(i,2); w = mst(i,3); plot([position(u,1) position(v,1)], [position(u,2) position(v,2)], 'k'); end for i = 1:length(centers) plot(position(centers(i),1), position(centers(i),2), 'o', 'MarkerFaceColor', colors(i)); end for i = 1:n d = inf; c = 0; for j = 1:length(centers) if dist(i,centers(j)) < d d = dist(i,centers(j)); c = j; end end plot([position(i,1) position(centers(c),1)], [position(i,2) position(centers(c),2)], colors(c)); end hold off; % 输出结果 disp(['总距离S1:' num2str(s1)]); disp(['维修道路总里程S2:' num2str(s2)]); end

Before Playstation, there was Pong, at one time the ultimate in video game entertainment. For those of you not familiar with this game please refer to the Wikipedia entry (http://en.wikipedia.org/wiki/Pong) and the many fine websites extolling the game and its virtues. Pong is not so very different in structure from the Billiard ball simulation that you developed earlier in the course. They both involve a ball moving and colliding with obstacles. The difference in this case is that two of the obstacles are under user control. The goal of this project is to develop your own version of Pong in MATLAB using the keyboard as input, for example, one player could move the left paddle up and down using the q and a keys while the right paddle is controlled with the p and l keys. You may check the code for the Lunarlander game which demonstrates some of the techniques you can use to capture user input. You will also probably find the plot, set, line and text commands useful in your program. You have used most of these before in the billiard simulation and you can use Matlabs online help to get more details on the many options these functions offer. Your program should allow you to play a game to 11 keeping track of score appropriately. The general structure of the code is outlined below in pseudo code While not done Update Ball State (position and velocity) taking into account collisions with walls and paddles Check for scoring and handle appropriately Update Display Note that in this case it is implicitly assumed that capturing the user input and moving the paddles is being handled with callback functions which removes that functionality from the main loop. For extra credit you could consider adding extra features like spin or gravity to the ball flight or providing a single player mode where the computer controls one of the paddles.

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