多元线性回归 fortran
时间: 2023-11-26 13:48:44 浏览: 91
根据提供的引用内容,我们可以了解到Fortran2013版可以用于对离散数据进行多元线性回归。下面是一个简单的多元线性回归的Fortran代码示例:
```fortran
program multiple_linear_regression
implicit none
integer, parameter :: dp = selected_real_kind(15, 307)
integer :: i, j, k, n, m
real(dp), dimension(:,:), allocatable :: x, y, xt, xtx, xtxi, b
real(dp), dimension(:), allocatable :: xmean, ymean, xstd, ystd
real(dp) :: r, ssr, sse, sst, yfit
character(len=100) :: filename
print *, "Enter the name of the data file:"
read *, filename
open(10, file=filename, status='old', action='read')
read(10,*) n, m
allocate(x(n,m), y(n))
do i = 1, n
read(10,*) (x(i,j), j=1,m), y(i)
end do
close(10)
allocate(xt(m,n))
do i = 1, n
do j = 1, m
xt(j,i) = x(i,j)
end do
end do
allocate(xtx(m,m))
do i = 1, m
do j = 1, m
xtx(i,j) = sum(xt(i,:)*x(:,j))
end do
end do
allocate(xtxi(m,m))
call matinv(xtx, xtxi)
allocate(b(m))
do i = 1, m
b(i) = sum(y*xt(i,:))*xtxi(i,i)
end do
allocate(xmean(m), xstd(m), ymean, ystd)
do i = 1, m
xmean(i) = sum(x(:,i))/n
xstd(i) = sqrt(sum((x(:,i)-xmean(i))**2)/(n-1))
do j = 1, n
x(j,i) = (x(j,i)-xmean(i))/xstd(i)
end do
end do
ymean = sum(y)/n
ystd = sqrt(sum((y-ymean)**2)/(n-1))
do i = 1, n
y(i) = (y(i)-ymean)/ystd
end do
sse = 0.0_dp
ssr = 0.0_dp
sst = 0.0_dp
do i = 1, n
yfit = 0.0_dp
do j = 1, m
yfit = yfit + b(j)*x(i,j)
end do
sse = sse + (y(i)-yfit)**2
ssr = ssr + (yfit-ymean)**2
sst = sst + (y(i)-ymean)**2
end do
r = sqrt(ssr/sst)
print *, "Regression coefficients:"
do i = 1, m
print *, "b(",i,") = ", b(i)
end do
print *, "Coefficient of determination:"
print *, "r = ", r
print *, "Residual standard error:"
print *, "s = ", sqrt(sse/(n-m))
deallocate(x, y, xt, xtx, xtxi, b, xmean, xstd, ymean, ystd)
end program multiple_linear_regression
```
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