S = a0 * b0 * pi
时间: 2023-09-07 17:12:46 浏览: 54
根据提供的引用内容,我们可以看到有三个旋转的代码实现。其中,引用给出了绕Y轴旋转的代码实现,引用给出了绕X轴旋转的代码实现,引用给出了绕Z轴旋转的代码实现。
根据引用和引用,我们可以得到点S绕Y轴旋转后的结果为outx = cos(thetay) * a0 * b0 * pi - sin(thetay) * 0,outz = cos(thetay) * 0 - sin(thetay) * a0 * b0 * pi。
根据引用,我们可以得到点S绕Z轴旋转后的结果为outx = cos(thetaz) * outx - sin(thetaz) * outy,outy = sin(thetaz) * outx + cos(thetaz) * outy。
综上所述,S = a0 * b0 * pi经过绕Y轴旋转和绕Z轴旋转后的结果可以表示为outx = cos(thetay) * a0 * b0 * pi - sin(thetay) * 0,outz = cos(thetay) * 0 - sin(thetay) * a0 * b0 * pi,outx = cos(thetaz) * outx - sin(thetaz) * outy,outy = sin(thetaz) * outx + cos(thetaz) * outy。<span class="em">1</span><span class="em">2</span><span class="em">3</span>
#### 引用[.reference_title]
- *1* *2* *3* [coding随笔 | 点绕向量旋转](https://blog.csdn.net/Ben_Pan1024/article/details/127226581)[target="_blank" data-report-click={"spm":"1018.2226.3001.9630","extra":{"utm_source":"vip_chatgpt_common_search_pc_result","utm_medium":"distribute.pc_search_result.none-task-cask-2~all~insert_cask~default-1-null.142^v93^chatsearchT3_1"}}] [.reference_item style="max-width: 100%"]
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