对于以上要求给出python代码
时间: 2023-07-22 13:01:21 浏览: 40
以下是一个示例的Python代码,来实现对比特流的采样和统计操作:
```python
import random
def generate_bitstream(size):
bitstream = [random.randint(0, 1) for _ in range(size)]
return bitstream
def proportion_sampling(bitstream, proportion):
sample_size = int(len(bitstream) * proportion)
sample = random.sample(bitstream, sample_size)
return sample
def fixed_size_sampling(bitstream, sample_size):
sample = random.sample(bitstream, sample_size)
return sample
def count_ones_last_n(bitstream, n):
last_n_elements = bitstream[-n:]
ones_count = last_n_elements.count(1)
return ones_count
# 比特流大小为 1,000,000
bitstream = generate_bitstream(1000000)
# 对比特流进行固定比例(10%)的采样
proportion = 0.1
proportion_sample = proportion_sampling(bitstream, proportion)
# 对比特流进行固定大小(1,000)的采样
fixed_size = 1000
fixed_size_sample = fixed_size_sampling(bitstream, fixed_size)
# 统计最后 N 个元素(N=50,000)中 1 的数量
n = 50000
ones_count = count_ones_last_n(bitstream, n)
# 输出结果
print("Proportion sampling result:", proportion_sample)
print("Fixed size sampling result:", fixed_size_sample)
print("Number of ones in the last", n, "elements:", ones_count)
```
请注意,以上代码只是示例,具体实现方式可能因实际需求而有所变化。你可以根据自己的具体场景和要求进行适当修改。