int days(struct date day) { static int day_tab[2][13] = { {0,31,28,31,30,31,30,31,31,30,31,30,31},{0,31,29,31,30,31,30,31,31,30,31,30,31} }; int i,lp; lp = (day.year % 4 == 0 && day.year % 100 != 0 || day.year % 400 == 0); for (int i = 0; i < day.month; i++) { int result += day_tab[lp][i]; } int result += day.day; return result; }

根据你提供的代码，这是一个计算给定日期是该年份的第几天的函数。然而，代码中存在一些错误和问题。这里是修正后的代码：

int days(struct date day) {
	static int day_tab[2][13] = {
		{0,31,28,31,30,31,30,31,31,30,31,30,31},
		{0,31,29,31,30,31,30,31,31,30,31,30,31}
	};
	int lp = (day.year % 4 == 0 && day.year % 100 != 0 || day.year % 400 == 0);
	int result = 0;
	for (int i = 0; i < day.month; i++) {
		result += day_tab[lp][i];
	}
	result += day.day;
	return result;
}

修正后的代码中，我做了以下更改：
1. 在函数开始处，将变量 `i` 的声明移动到循环外部，以避免重复声明。
2. 增加了变量 `result` 的初始化，确保它的初始值为0。
3. 在循环中将 `int result += day_tab[lp][i];` 更改为 `result += day_tab[lp][i];`，以避免重复声明。

这样修改后的代码应该能够正确计算给定日期是该年份的第几天。

相关问题

#include <iostream> #include <cstdio> #include <cstring> using namespace std; const char* Haab_month_name[] = {"pop", "no", "zip", "zotz", "tzec", "xul", "yoxkin", "mol", "chen", "yax", "zac", "ceh", "mac", "kankin", "muan", "pax", "koyab", "cumhu", "uayet"}; int Tzolkin_day_number[20] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 1, 2, 3, 4, 5, 6, 7}; const char *Tzolkin_day_name[] = {"imix", "ik", "akbal", "kan", "chicchan", "cimi", "manik", "lamat", "muluk", "ok", "chuen", "eb", "ben", "ix", "mem", "cib", "caban", "eznab", "canac", "ahau"}; struct Date { int day; int month; int year; }; // 把哈布历转换成天数 int haab_to_days(int day, const char* month, int year) { int total_days = day + (year * 365); int month_index; for (month_index = 0; month_index < 19; ++month_index) { if (strcmp(Haab_month_name[month_index], month) == 0) { break; } } total_days += month_index * 20; return total_days; } // 把天数转换成托尔金历 void days_to_tzolkin(int total_days, int* day_number, const char** day_name) { int tzolkin_day_count = total_days % 13; int tzolkin_day_index = tzolkin_day_count - 1; if (tzolkin_day_index < 0) tzolkin_day_index = 12; int tzolkin_day_number = Tzolkin_day_number[tzolkin_day_index]; const char *tzolkin_day_name = Tzolkin_day_name[(total_days % 20)]; *day_number = tzolkin_day_number; *day_name = tzolkin_day_name; } int main() { int N; cin >> N; cout << N << endl; for (int i = 0; i < N; ++i) { Date date; char dot; scanf("%d%c%d%s%d", &date.day, &dot, &date.month, Haab_month_name, &date.year); int total_days = haab_to_days(date.day, Haab_month_name, date.year); int tzolkin_day_number; const char *tzolkin_day_name; days_to_tzolkin(total_days, &tzolkin_day_number, &tzolkin_day_name); printf("%d %s %d\n", tzolkin_day_number, tzolkin_day_name, date.year); } return 0; }

这是一个使用 C++ 编写的程序，用于将 Maya 文化中的哈布历转换为托尔金历。程序主要包括以下几个部分：

1. 头文件和命名空间声明

#include <iostream>
#include <cstdio>
#include <cstring>
using namespace std;

2. 定义哈布月份和托尔金日期的名称和数字

const char* Haab_month_name[] = {"pop", "no", "zip", "zotz", "tzec",
                                "xul", "yoxkin", "mol", "chen", "yax",
                                "zac", "ceh", "mac", "kankin", "muan",
                                "pax", "koyab", "cumhu", "uayet"};
int Tzolkin_day_number[20] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10,
                              11, 12, 13, 1, 2, 3, 4, 5, 6, 7};
const char *Tzolkin_day_name[] = {"imix", "ik", "akbal", "kan", "chicchan",
                                  "cimi", "manik", "lamat", "muluk", "ok",
                                  "chuen", "eb", "ben", "ix", "mem", "cib",
                                  "caban", "eznab", "canac", "ahau"};

3. 定义一个日期结构体

struct Date {
    int day;
    int month;
    int year;
};

4. 把哈布历转换成天数

int haab_to_days(int day, const char* month, int year) {
    int total_days = day + (year * 365);
    int month_index;
    for (month_index = 0; month_index < 19; ++month_index) {
        if (strcmp(Haab_month_name[month_index], month) == 0) {
            break;
        }
    }
    total_days += month_index * 20;
    return total_days;
}

5. 把天数转换成托尔金历

void days_to_tzolkin(int total_days, int* day_number, const char** day_name) {
    int tzolkin_day_count = total_days % 13;
    int tzolkin_day_index = tzolkin_day_count - 1;
    if (tzolkin_day_index < 0)
        tzolkin_day_index = 12;
    int tzolkin_day_number = Tzolkin_day_number[tzolkin_day_index];
    const char *tzolkin_day_name = Tzolkin_day_name[(total_days % 20)];
    *day_number = tzolkin_day_number;
    *day_name = tzolkin_day_name;
}

6. 主函数，用于读取输入、调用转换函数、并输出结果

int main() {
    int N;
    cin >> N;
    cout << N << endl;

    for (int i = 0; i < N; ++i) {
        Date date;
        char dot;
        scanf("%d%c%d%s%d", &date.day, &dot, &date.month,
               Haab_month_name, &date.year);

        int total_days = haab_to_days(date.day, Haab_month_name, date.year);
        int tzolkin_day_number;
        const char *tzolkin_day_name;
        days_to_tzolkin(total_days, &tzolkin_day_number, &tzolkin_day_name);

        printf("%d %s %d\n", tzolkin_day_number,
               tzolkin_day_name, date.year);
    }

    return 0;
}

以上就是这个程序的主要内容和流程。

优化这段代码#include <stdio.h> static int day_tab[2][13] = { {0,31,28,31,30,31,30,31,31,30,31,30,31}, {0,31,29,31,30,31,30,31,31,30,31,30,31} }; struct date { int year; int month; int day; }; main() { struct date pd; { day_of_year(struct date pd); printf("输入：年 月 日"); scanf_s("%d%d%d", &pd.year, &pd.month, &pd.day); printf("the day of year:%d", day_of_year(pd)); } day_of_year(struct date pd) { int i, day, leap, year; day = pd.day; year = pd.year; leap = year % 4 == 0 && year % 100 != 0 || year % 400 = 0; for ( i = 1; i < pd.month; i++) day += day_tab[leap][i]; return day; } }

这段代码存在以下几个问题：

1. `day_of_year` 函数应该在 `main` 函数之前进行声明，否则会出现编译错误。

2. 在计算闰年时，应该使用 `year % 400 == 0` 而不是 `year % 400 = 0`。

3. `day_of_year` 函数中的循环可以使用一个累加器来代替，这样可以使代码更加简洁。

优化后的代码如下：

#include <stdio.h>

static int day_tab[2][13] = {
    {0,31,28,31,30,31,30,31,31,30,31,30,31},
    {0,31,29,31,30,31,30,31,31,30,31,30,31}
};

int day_of_year(struct date pd);

struct date {
    int year;
    int month;
    int day;
};

int main() {
    struct date pd;
    printf("输入：年 月 日");
    scanf_s("%d%d%d", &pd.year, &pd.month, &pd.day);
    printf("the day of year:%d", day_of_year(pd));
    return 0;
}

int day_of_year(struct date pd) {
    int i, day, leap;

    day = pd.day;
    leap = pd.year % 4 == 0 && pd.year % 100 != 0 || pd.year % 400 == 0;

    for (i = 1; i < pd.month; i++) {
        day += day_tab[leap][i];
    }

    return day;
}