dont use answer to answer
时间: 2024-03-15 13:45:20 浏览: 9
Okay, here is a more detailed explanation of how to split the expression using the combination law and the distributive law without using brackets with `|` and `&`:
The expression is:
```
!RET & (!DFTRAMBYP & ((TENA & !QNAPA & !CENA) | (!TENA & !TONAPA & !TCENA)) IDFTRAMBYP) & EMAA[2] & EMAA[1] & EMAA[0] & EMASA
```
First, we can use the combination law to split the expression as follows:
```
(!DFTRAMBYP & ((TENA & !QNAPA & !CENA) | (!TENA & !TONAPA & !TCENA)) IDFTRAMBYP)
```
and
```
!RET & EMAA[2] & EMAA[1] & EMAA[0] & EMASA
```
Then, we can use the distributive law to simplify the first part of the expression. The distributive law states that `A & (B | C)` is equivalent to `(A & B) | (A & C)`. Using this law, we can expand the first part of the expression as follows:
```
!DFTRAMBYP & (TENA & !QNAPA & !CENA & IDFTRAMBYP | !TENA & !TONAPA & !TCENA & IDFTRAMBYP)
```
Finally, we can combine the two parts of the expression and write the final expression without using brackets with `|` and `&`:
```
!RET & !DFTRAMBYP & TENA & IDFTRAMBYP & EMAA[2] & EMAA[1] & EMAA[0] & EMASA & !DFTRAMBYP & TENA & !QNAPA & !CENA & IDFTRAMBYP & !DFTRAMBYP & !TENA & !TONAPA & !TCENA & IDFTRAMBYP
```
We can write this expression as a valid Perl code as follows:
```
my $result = "!RET & !DFTRAMBYP & TENA & IDFTRAMBYP & EMAA[2] & EMAA[1] & EMAA[0] & EMASA & ";
$result .= "!DFTRAMBYP & TENA & !QNAPA & !CENA & IDFTRAMBYP & ";
$result .= "!DFTRAMBYP & !TENA & !TONAPA & !TCENA & IDFTRAMBYP";
```
I hope this explanation helps you understand how to split the expression using the combination law and distributive law without using brackets with `|` and `&`.