帮我用javascript写一个Delaunay算法

好的，以下是使用 JavaScript 实现 Delaunay 算法的代码：

function Triangle(v1, v2, v3) {
  this.v1 = v1;
  this.v2 = v2;
  this.v3 = v3;
}

function Edge(v1, v2) {
  this.v1 = v1;
  this.v2 = v2;
}

function delaunay(points) {
  var triangles = [];

  // Create a super triangle that covers all the points
  var superTriangle = new Triangle(
    { x: -Number.MAX_VALUE, y: -Number.MAX_VALUE },
    { x: 0, y: Number.MAX_VALUE },
    { x: Number.MAX_VALUE, y: -Number.MAX_VALUE }
  );
  triangles.push(superTriangle);

  // Add each point to the Delaunay triangulation
  for (var i = 0; i < points.length; i++) {
    var edges = [];

    // Find all the edges of the triangles that intersect with the new point
    for (var j = 0; j < triangles.length; j++) {
      var t = triangles[j];
      if (circumCircleContains(t, points[i])) {
        edges.push(new Edge(t.v1, t.v2));
        edges.push(new Edge(t.v2, t.v3));
        edges.push(new Edge(t.v3, t.v1));
        triangles.splice(j, 1);
        j--;
      }
    }

    // Remove duplicate edges
    for (var j = 0; j < edges.length; j++) {
      for (var k = j + 1; k < edges.length; k++) {
        if (
          (edges[j].v1 == edges[k].v1 && edges[j].v2 == edges[k].v2) ||
          (edges[j].v1 == edges[k].v2 && edges[j].v2 == edges[k].v1)
        ) {
          edges.splice(k, 1);
          k--;
          edges.splice(j, 1);
          j--;
          break;
        }
      }
    }

    // Create new triangles using the new point
    for (var j = 0; j < edges.length; j++) {
      triangles.push(new Triangle(edges[j].v1, edges[j].v2, points[i]));
    }
  }

  // Remove any triangles that share vertices with the super triangle
  for (var i = 0; i < triangles.length; i++) {
    var t = triangles[i];
    if (t.v1 == superTriangle.v1 || t.v1 == superTriangle.v2 || t.v1 == superTriangle.v3 ||
        t.v2 == superTriangle.v1 || t.v2 == superTriangle.v2 || t.v2 == superTriangle.v3 ||
        t.v3 == superTriangle.v1 || t.v3 == superTriangle.v2 || t.v3 == superTriangle.v3) {
      triangles.splice(i, 1);
      i--;
    }
  }

  return triangles;
}

function circumCircleContains(triangle, point) {
  // Calculate the circumcircle of the triangle
  var deltaA = triangle.v1.x * triangle.v1.x + triangle.v1.y * triangle.v1.y;
  var deltaB = triangle.v2.x * triangle.v2.x + triangle.v2.y * triangle.v2.y;
  var deltaC = triangle.v3.x * triangle.v3.x + triangle.v3.y * triangle.v3.y;
  var axb = triangle.v1.x * (triangle.v2.y - triangle.v3.y) +
            triangle.v2.x * (triangle.v3.y - triangle.v1.y) +
            triangle.v3.x * (triangle.v1.y - triangle.v2.y);
  var center = {
    x: ((deltaA * (triangle.v2.y - triangle.v3.y) +
          deltaB * (triangle.v3.y - triangle.v1.y) +
          deltaC * (triangle.v1.y - triangle.v2.y)) /
          (2 * axb)),
    y: ((deltaA * (triangle.v3.x - triangle.v2.x) +
          deltaB * (triangle.v1.x - triangle.v3.x) +
          deltaC * (triangle.v2.x - triangle.v1.x)) /
          (2 * axb))
  };
  var radius = Math.sqrt(Math.pow(center.x - triangle.v1.x, 2) +
                         Math.pow(center.y - triangle.v1.y, 2));

  // Check if the point is inside the circumcircle
  var deltaPoint = point.x * point.x + point.y * point.y;
  return deltaPoint <= Math.pow(radius, 2);
}

这段代码实现了基本的 Delaunay 三角剖分算法，可以将给定的一系列点（Point）进行三角剖分并得到对应的三角形（Triangle）列表。