我不要伪码,我要完整的c#代码
时间: 2023-08-07 07:41:54 浏览: 38
好的,以下是用 C# 实现银行家算法的完整代码:
```csharp
using System;
using System.Collections.Generic;
namespace BankersAlgorithm
{
class Program
{
static void Main(string[] args)
{
// 输入进程个数、进程资源个数、所有进程的Allocation(单个进程的资源之间以空格间隔,进程之间以分号间隔,如1 2 3;4 5 6)
Console.Write("请输入进程个数:");
int n = int.Parse(Console.ReadLine());
Console.Write("请输入进程资源个数:");
int m = int.Parse(Console.ReadLine());
int[,] max = new int[n, m];
int[,] allocation = new int[n, m];
int[,] need = new int[n, m];
int[] available = new int[m];
Console.WriteLine("请输入所有进程的Allocation(单个进程的资源之间以空格间隔,进程之间以分号间隔):");
for (int i = 0; i < n; i++)
{
string[] line = Console.ReadLine().Split(';');
for (int j = 0; j < m; j++)
{
allocation[i, j] = int.Parse(line[j].Trim());
}
}
Console.Write("请输入可用资源:");
string[] available_line = Console.ReadLine().Split(' ');
for (int i = 0; i < m; i++)
{
available[i] = int.Parse(available_line[i]);
}
// 计算 need 矩阵
for (int i = 0; i < n; i++)
{
for (int j = 0; j < m; j++)
{
need[i, j] = max[i, j] - allocation[i, j];
}
}
// 执行银行家算法
bool[] finish = new bool[n];
int[] work = new int[m];
for (int i = 0; i < m; i++)
{
work[i] = available[i];
}
List<int> safe_sequence = new List<int>();
while (true)
{
bool found = false;
for (int i = 0; i < n; i++)
{
if (!finish[i])
{
bool can_finish = true;
for (int j = 0; j < m; j++)
{
if (need[i, j] > work[j])
{
can_finish = false;
break;
}
}
if (can_finish)
{
for (int j = 0; j < m; j++)
{
work[j] += allocation[i, j];
}
finish[i] = true;
safe_sequence.Add(i);
found = true;
}
}
}
if (!found)
{
break;
}
}
// 输出结果
if (safe_sequence.Count == n)
{
Console.WriteLine("安全序列:");
foreach (int i in safe_sequence)
{
Console.Write("{0} ", i);
}
Console.WriteLine();
Console.WriteLine("安全序列数量:{0}", safe_sequence.Count);
}
else
{
Console.WriteLine("申请的资源不符合条件!请重新输入!");
}
}
}
}
```
请注意,这只是一份简单的实现示例,可能需要根据实际情况进行修改和优化。如果您有任何问题或疑问,请随时提出。