七段数码管绘制python代码
时间: 2023-10-14 11:23:36 浏览: 107
很高兴回答您的问题。以下是一个七段数码管绘制的Python代码示例:
```python
# 导入必要的库
import turtle
# 定义绘制数字的函数
def draw_number(number, turtle, size):
# 定义每个数字对应的七段数码管的状态(0表示关闭,1表示打开)
segments = [
[1, 1, 1, 1, 1, 1, 0], # 0
[0, 1, 1, 0, 0, 0, 0], # 1
[1, 1, 0, 1, 1, 0, 1], # 2
[1, 1, 1, 1, 0, 0, 1], # 3
[0, 1, 1, 0, 0, 1, 1], # 4
[1, 0, 1, 1, 0, 1, 1], # 5
[1, 0, 1, 1, 1, 1, 1], # 6
[1, 1, 1, 0, 0, 0, 0], # 7
[1, 1, 1, 1, 1, 1, 1], # 8
[1, 1, 1, 1, 0, 1, 1], # 9
]
# 根据数字绘制七段数码管
for i, segment in enumerate(segments[number]):
if segment == 1:
turtle.color("red")
else:
turtle.color("gray")
if i == 0:
turtle.penup()
turtle.goto(-size / 2, size)
turtle.pendown()
turtle.setheading(0)
elif i == 1:
turtle.penup()
turtle.goto(size / 2, size)
turtle.pendown()
turtle.setheading(0)
elif i == 2:
turtle.penup()
turtle.goto(size / 2, 0)
turtle.pendown()
turtle.setheading(90)
elif i == 3:
turtle.penup()
turtle.goto(size / 2, -size)
turtle.pendown()
turtle.setheading(90)
elif i == 4:
turtle.penup()
turtle.goto(-size / 2, -size)
turtle.pendown()
turtle.setheading(180)
elif i == 5:
turtle.penup()
turtle.goto(-size / 2, 0)
turtle.pendown()
turtle.setheading(180)
elif i == 6:
turtle.penup()
turtle.goto(-size / 2, size)
turtle.pendown()
turtle.setheading(270)
turtle.forward(size)
# 创建画布和海龟对象
canvas = turtle.Screen()
canvas.bgcolor("white")
turtle = turtle.Turtle()
turtle.speed(0)
turtle.hideturtle()
# 绘制数字
number = input("请输入要显示的数字(0~9):")
size = int(input("请输入七段数码管的尺寸:"))
for i in number:
draw_number(int(i), turtle, size)
turtle.penup()
turtle.forward(1.5 * size)
turtle.pendown()
# 隐藏海龟对象并退出画布
turtle.hideturtle()
canvas.exitonclick()
```
希望这个代码示例能够帮助您。如果您有任何其他问题,欢迎随时向我提问。
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