python1、计算前n个自然数的阶乘之和1!+2!+3!+...+n!的值
时间: 2023-11-24 22:51:54 浏览: 40
以下是三种Python计算前n个自然数的阶乘之和的方法:
方法一:
```python
n = int(input())
b = 1
sum = 0
for i in range(1, n+1):
b = b * i
sum += b
print(sum)
```
方法二:
```python
i = int(input())
sum = 0
if i < 1:
exit()
else:
while i > 0:
b = 2
c = 1
while b <= i:
c = b * c
b = b + 1
sum += c
i = i - 1
print(sum)
```
方法三:
```python
def factorial(n):
if n == 0:
return 1
else:
return n * factorial(n-1)
n = int(input())
sum = 0
for i in range(1, n+1):
sum += factorial(i)
print(sum)
```
相关问题
用Python计算前n个自然数的阶乘之和1!+21+3!+...+n!的值
以下是用Python计算前n个自然数的阶乘之和的代码:
```python
def factorial(n):
if n == 0:
return 1
else:
return n * factorial(n-1)
def sum_factorial(n):
total = 0
for i in range(1, n+1):
total += factorial(i)
return total
n = int(input("请输入你要求的前n个数的阶乘的和: "))
result = sum_factorial(n)
print("1! + 2! + 3! + ... + n! 的值为:", result)
```
这段代码首先定义了一个递归函数`factorial`,用于计算一个数的阶乘。然后定义了一个函数`sum_factorial`,用于计算前n个自然数的阶乘之和。最后,通过用户输入的n值,调用`sum_factorial`函数并打印结果。
python计算前n个自然数的阶乘之和1!+2!+3!+...+n!
以下是Python计算前n个自然数的阶乘之和的代码实现:
```python
def factorial(n):
if n == 0:
return 1
else:
return n * factorial(n-1)
def sum_factorial(n):
sum = 0
for i in range(1, n+1):
sum += factorial(i)
return sum
n = int(input("请输入你要求的前n个数的阶乘的和:"))
print("前n个数的阶乘的和为:", sum_factorial(n))
```