C++ 经纬度转化为度分秒格式的函数

以下是将经度和纬度分别转换为度分秒格式的函数:

// 经度转换为度分秒格式
void convert_longitude(double longitude, int &Degrees, int &Minutes, int &Seconds) {
    Degrees = int(longitude);
    double fractional_part = longitude - Degrees;
    Minutes = int(fractional_part * 60);
    Seconds = int((fractional_part * 60 - Minutes) * 60);
}

// 维度转换为度分秒格式
void convert_latitude(double latitude, int &Degrees, int &Minutes, int &Seconds) {
    Degrees = int(latitude);
    double fractional_part = latitude - Degrees;
    Minutes = int(fractional_part * 60);
    Seconds = int((fractional_part * 60 - Minutes) * 60);
}

使用方法如下：

int main() {
    double longitude = 116.405285; // 116.405285°E
    double latitude = 39.904989; // 39.904989°N

    int longitude_degrees, longitude_minutes, longitude_seconds;
    convert_longitude(longitude, longitude_degrees, longitude_minutes, longitude_seconds);

    int latitude_degrees, latitude_minutes, latitude_seconds;
    convert_latitude(latitude, latitude_degrees, latitude_minutes, latitude_seconds);

    cout << "Longitude: " << longitude_degrees << "°" << longitude_minutes << "'" << longitude_seconds << "\"" << endl;
    cout << "Latitude: " << latitude_degrees << "°" << latitude_minutes << "'" << latitude_seconds << "\"" << endl;

    return 0;
}

输出结果为：

Longitude: 116°24'19"
Latitude: 39°54'18"