string='abc' list=['a', 'b', 'c'] tuple=('a', 'b','c') with open(test.txt', 'w') as f: f.write(string+'n') f.write(str(list)+'\n') f.write(str(tuple)) with open(test.txt','r') as f: print(f.readline（））

这里的代码将字符串'abc'、列表[‘a’,‘b’,‘c’]和元组（‘a’,‘b’,‘c’）写入一个叫test.txt的文件中，最后将文件中的内容输出到屏幕上，即'abc'、[‘a’,‘b’,‘c’]和（‘a’,‘b’,‘c’）。

相关问题

class B(): """注释""" def __init__(self, a, b, c, d): self.a = a self.b = b self.c = c self.d = d def fget(self): return self.a, self.b, self.c, self.d def fset(self, num): self.a, self.b, self.c, self.d = num def fdel(self): self.a, self.b, self.c, self.d = 0, 0, 0, 0 num = property(fget, fset, fdel, "property试运行方法") test_ = B(1, 2, 3, 4)为什么会输出Built-in immutable sequence. If no argument is given, the constructor returns an empty tuple. If iterable is specified the tuple is initialized from iterable's items. If the argument is a tuple, the return value is the same object.

It seems that the output you mentioned is not related to the code you provided. The code defines a class B with a property called "num", which can be used to get or set the values of four attributes (a, b, c, d) of an instance of the class B.

The line "test_ = B(1, 2, 3, 4)" creates an instance of the class B with initial values of 1, 2, 3, and 4 for its four attributes.

Unless there is some other code that you did not provide, there should be no output from running this code.

6.以下关于Python函数说法正确的是（） def fib(n): a,b=1,1 for i in range(n-1): a,b=b,a+b return a,b print(fib(4)) A.a = 3 B.b=2 C.a=6 D.b=5

正确答案是 None。题目中给出的函数是一个斐波那契数列生成函数，它的返回值是一个元组（tuple），包含了前 n 个斐波那契数列的值。在主程序中，`print(fib(4))` 会输出 `(2, 3)`，即前 4 个斐波那契数列的值为 1、1、2 和 3。

题目中并没有涉及到变量赋值的情况，因此选项 A、B、C 和 D 都不正确。