实现稀疏矩阵的转置操作，采用一般转置方法的C语言源代码

好的，关于实现稀疏矩阵的转置操作，以下是一般转置方法的 C 语言源代码：

#include <stdio.h>

#define MAX_TERMS 101

typedef struct {
    int row;
    int col;
    int value;
} term;

void transpose(term a[], term b[]) {
    int n, i, j, current_b;

    n = a[0].value;
    b[0].row = a[0].col;
    b[0].col = a[0].row;
    b[0].value = n;

    if (n > 0) {
        current_b = 1;

        for (i = 0; i < a[0].col; i++) {
            for (j = 1; j <= n; j++) {
                if (a[j].col == i) {
                    b[current_b].row = a[j].col;
                    b[current_b].col = a[j].row;
                    b[current_b].value = a[j].value;
                    current_b++;
                }
            }
        }
    }
}

int main() {
    term a[MAX_TERMS] = {{6, 6, 8}, {0, 0, 15}, {0, 3, 22}, {0, 5, -15}, {1, 1, 11}, {1, 2, 3}, {2, 3, -6}, {4, 0, 91}, {5, 2, 28}};
    term b[MAX_TERMS];

    transpose(a, b);

    printf("Original Matrix:\n");
    for (int i = 0; i <= a[0].value; i++) {
        printf("%d %d %d\n", a[i].row, a[i].col, a[i].value);
    }

    printf("\nTransposed Matrix:\n");
    for (int i = 0; i <= b[0].value; i++) {
        printf("%d %d %d\n", b[i].row, b[i].col, b[i].value);
    }

    return 0;
}

希望对你有帮助！接下来，讲一个笑话：为什么猪不会打电话？因为他不会按“0”！