用 for 循环写Define a function even_sum(num), where num is a positive number. The function iterates all the integers numbers from 0 to num, sums them up if they are even numbers, and returns the sum.

好的，下面是用 for 循环实现的 even_sum(num) 函数的代码：

def even_sum(num):
    sum = 0
    for i in range(num+1):
        if i % 2 == 0:
            sum += i
    return sum

这个函数的思路是先定义一个 sum 变量，然后用 for 循环遍历 0 到 num 之间的所有整数。在循环中，如果当前的数是偶数，就把它加到 sum 变量中。最后返回 sum 变量的值即可。

相关问题

The task of this problem is simple: insert a sequence of distinct positive integers into a hash table, and output the positions of the input numbers. The hash function is defined to be H(key)=key%TSize where TSize is the maximum size of the hash table. Quadratic probing (with positive increments only) is used to solve the collisions. Note that the table size is better to be prime. If the maximum size given by the user is not prime, you must re-define the table size to be the smallest prime number which is larger than the size given by the user. Input Specification: Each input file contains one test case. For each case, the first line contains two positive numbers: MSize (≤10 4 ) and N (≤MSize) which are the user-defined table size and the number of input numbers, respectively. Then N distinct positive integers are given in the next line. All the numbers in a line are separated by a space. Output Specification: For each test case, print the corresponding positions (index starts from 0) of the input numbers in one line. All the numbers in a line are separated by a space, and there must be no extra space at the end of the line. In case it is impossible to insert the number, print "-" instead.

这道题的任务很简单：将一串不同的正整数插入哈希表中，并输出输入数字的位置。哈希函数的定义为 H(key)=key%TSize，其中 TSize 是哈希表的最大大小。使用二次探测（只增加正数）来解决碰撞。注意，表格大小最好为质数。如果用户给出的最大大小不是质数，则必须重新定义表格大小为大于用户给出大小的最小质数。

输入格式：每个输入文件包含一个测试用例。对于每种情况，第一行包含两个正数：MSize（≤10 4）和N（≤MSize），它们是用户定义的表大小和输入数字的数量。然后，在下一行中给出N个不同的正整数。一行中的所有数字由空格分隔。

输出格式：对于每个测试用例，在一行中打印输入数字的相应位置（索引从0开始）。一行中的所有数字由空格分隔，行末不能有多余的空格。如果无法插入数字，则打印“-”。

In this problem, you will write a function called calc_sum that takes an integer argument and prints the sum of all integer from 0 up to and including the integer argument. The function should print the result before returning. You only need to define the function, calc_sum. for example, >>> calc_sum(3) 6 >>> calc_sum(4) 10 Requirements: (1) use range function (2) argument is n (3) use loop (4) local variable sum and loop variable value

Sure, I can help you with that! Here's the code for the `calc_sum` function that meets all the requirements you specified:

def calc_sum(n):
    sum = 0
    for value in range(n+1):
        sum += value
    print(sum)

To explain the code a bit: we first initialize a local variable `sum` to 0, which we will use to keep track of the running sum. We then use a `for` loop to iterate over the range from 0 to `n+1` (inclusive). For each value in this range, we add it to the running sum. Finally, we print out the sum using the `print` function.

You can call this function with an integer argument like so:

calc_sum(3) # prints 6
calc_sum(4) # prints 10

Let me know if you have any other questions!