pucOtherPublicKey->bits = uiKeyLength; pucOtherTmpPublicKey->bits = uiKeyLength; pucSelfPrivateKey->bits = uiKeyLength; pucSelfPublicKey->bits = uiKeyLength; pucSelfTmpPrivateKey->bits = uiKeyLength; pucSelfTmpPublicKey->bits = uiKeyLength;有什么快捷方式替代吗
时间: 2024-03-21 21:38:41 浏览: 10
可以将这些语句简化为一个循环,避免重复的代码,如下所示:
```
int uiKeyLength = 1024; // 假设 key length 为 1024
unsigned char** pucPointers[6] = {
&pucOtherPublicKey->bits,
&pucOtherTmpPublicKey->bits,
&pucSelfPrivateKey->bits,
&pucSelfPublicKey->bits,
&pucSelfTmpPrivateKey->bits,
&pucSelfTmpPublicKey->bits
};
for (int i = 0; i < 6; i++) {
*pucPointers[i] = uiKeyLength;
}
```
这样可以避免重复的代码,并且让代码更加简洁易读。
相关问题
#include<bits/stdc++.h> using namespace std; typedef struct Node * ptrtonode; typedef struct Node { int data,order; ptrtonode next; } node; int main() { ptrtonode head=new node(); head->next=NULL; int n,a,b; char c; scanf("%d",&n); int o=1; for(int i=1; i<=n; i++) { ptrtonode q; ptrtonode p; cin>>c; if(c=='H') { p=new node(); scanf("%d",&a); p->data=a; p->order=o; o++; p->next=head->next; head->next=p; } else if(c=='D') { cin>>a; if(a==0) { p=head->next; head->next=p->next; free(p); } else { q=head->next; while(q->order!=o) { q=q->next; } p=q->next; q->next=p->next; } } else if(c=='I') { scanf("%d%d",&a,&b); p=head->next; while(p->order!=a) { p=p->next; } q=new node(); q->data=b; q->order=o; o++; q->next=p->next; p->next=q; } } head=head->next; while(head) { cout<<head->data<<" "<<head->order<<endl; head=head->next; } return 0; }哪里有错误
这段代码的错误是使用了 `free()` 函数,而 `free()` 函数是 C 语言的函数,在 C++ 中应该使用 `delete` 或 `delete[]` 来释放内存。另外,使用 `cin` 读入字符时应该加上 `#include <iostream>`。下面是修改过的代码:
```c++
#include<iostream>
using namespace std;
typedef struct Node * ptrtonode;
typedef struct Node {
int data, order;
ptrtonode next;
} node;
int main() {
ptrtonode head = new node();
head->next = NULL;
int n, a, b;
char c;
cin >> n;
int o = 1;
for(int i = 1; i <= n; i++) {
ptrtonode q;
ptrtonode p;
cin >> c;
if(c == 'H') {
p = new node();
cin >> a;
p->data = a;
p->order = o;
o++;
p->next = head->next;
head->next = p;
}
else if(c == 'D') {
cin >> a;
if(a == 0) {
p = head->next;
head->next = p->next;
delete p;
}
else {
q = head->next;
while(q->order != o) {
q = q->next;
}
p = q->next;
q->next = p->next;
delete p;
}
}
else if(c == 'I') {
cin >> a >> b;
p = head->next;
while(p->order != a) {
p = p->next;
}
q = new node();
q->data = b;
q->order = o;
o++;
q->next = p->next;
p->next = q;
}
}
head = head->next;
while(head) {
cout << head->data << " " << head->order << endl;
head = head->next;
}
return 0;
}
```
TIM4->SR=TIM4->SR&0XA1A0
& ~(1<<0);
This code clears the update interrupt flag (UIF) in the status register (SR) of timer 4. The bitmask "(1<<0)" is used to select the first bit, which corresponds to the UIF. By performing a bitwise NOT operation on this bitmask and then ANDing it with the SR, we clear the UIF bit while leaving all other bits unchanged. The result is then written back to the SR register. This code is typically used in the interrupt service routine (ISR) for timer 4, to acknowledge and clear the interrupt flag after the update event has been handled.
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