用c语言写一个具有对局回放功能的五子棋小游戏

好的，我可以为您提供一个五子棋小游戏的基本代码，包括对局回放功能，代码如下：

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <time.h>

#define BOARD_SIZE 15 // 棋盘大小
#define EMPTY 0 // 空格
#define BLACK 1 // 黑棋
#define WHITE 2 // 白棋

// 棋盘
int board[BOARD_SIZE][BOARD_SIZE];

// 保存每一步的信息
typedef struct {
    int x;
    int y;
    int player;
} Step;

// 保存所有的步骤
Step steps[BOARD_SIZE * BOARD_SIZE];
int stepCount = 0;

// 初始化棋盘
void initBoard() {
    memset(board, EMPTY, sizeof(board));
}

// 打印棋盘
void printBoard() {
    printf("   ");
    for (int i = 0; i < BOARD_SIZE; i++) {
        printf("%2d ", i);
    }
    printf("\n");
    for (int i = 0; i < BOARD_SIZE; i++) {
        printf("%2d ", i);
        for (int j = 0; j < BOARD_SIZE; j++) {
            if (board[i][j] == EMPTY) {
                printf(".  ");
            } else if (board[i][j] == BLACK) {
                printf("X  ");
            } else {
                printf("O  ");
            }
        }
        printf("\n");
    }
}

// 判断胜负
int checkWin(int player) {
    int count = 0;

    // 判断横向
    for (int i = 0; i < BOARD_SIZE; i++) {
        count = 0;
        for (int j = 0; j < BOARD_SIZE; j++) {
            if (board[i][j] == player) {
                count++;
                if (count == 5) {
                    return 1;
                }
            } else {
                count = 0;
            }
        }
    }

    // 判断纵向
    for (int i = 0; i < BOARD_SIZE; i++) {
        count = 0;
        for (int j = 0; j < BOARD_SIZE; j++) {
            if (board[j][i] == player) {
                count++;
                if (count == 5) {
                    return 1;
                }
            } else {
                count = 0;
            }
        }
    }

    // 判断正对角线
    for (int i = 0; i < BOARD_SIZE - 4; i++) {
        for (int j = 0; j < BOARD_SIZE - 4; j++) {
            count = 0;
            for (int k = 0; k < 5; k++) {
                if (board[i+k][j+k] == player) {
                    count++;
                    if (count == 5) {
                        return 1;
                    }
                } else {
                    count = 0;
                }
            }
        }
    }

    // 判断反对角线
    for (int i = 0; i < BOARD_SIZE - 4; i++) {
        for (int j = 4; j < BOARD_SIZE; j++) {
            count = 0;
            for (int k = 0; k < 5; k++) {
                if (board[i+k][j-k] == player) {
                    count++;
                    if (count == 5) {
                        return 1;
                    }
                } else {
                    count = 0;
                }
            }
        }
    }

    return 0;
}

// 保存步骤
void saveStep(int x, int y, int player) {
    Step step;
    step.x = x;
    step.y = y;
    step.player = player;
    steps[stepCount++] = step;
}

// 悔棋
void undo() {
    if (stepCount == 0) {
        printf("已经没有步骤可以悔了！\n");
        return;
    }

    Step step = steps[--stepCount];
    board[step.x][step.y] = EMPTY;
    printf("悔棋成功！\n");
}

// 对局回放
void replay() {
    for (int i = 0; i < stepCount; i++) {
        Step step = steps[i];
        board[step.x][step.y] = step.player;
        printBoard();
        printf("\n");
        printf("%c 下在 (%d, %d)\n", step.player == BLACK ? 'X' : 'O', step.x, step.y);
        printf("按任意键继续...\n");
        getchar();
    }
}

int main() {
    srand(time(NULL));
    initBoard();
    printBoard();

    int player = BLACK;
    while (1) {
        int x, y;
        printf("%c 的回合，请输入落子位置（x, y）：", player == BLACK ? 'X' : 'O');
        scanf("%d%d", &x, &y);
        if (x < 0 || x >= BOARD_SIZE || y < 0 || y >= BOARD_SIZE) {
            printf("位置无效，请重新输入！\n");
            continue;
        }
        if (board[x][y] != EMPTY) {
            printf("该位置已经有子，请重新输入！\n");
            continue;
        }
        board[x][y] = player;
        saveStep(x, y, player);
        printBoard();
        if (checkWin(player)) {
            printf("%c 获胜！\n", player == BLACK ? 'X' : 'O');
            break;
        }
        if (stepCount == BOARD_SIZE * BOARD_SIZE) {
            printf("平局！\n");
            break;
        }
        player = player == BLACK ? WHITE : BLACK;
    }

    printf("按 1 回放对局，按其他键退出：");
    int choice;
    scanf("%d", &choice);
    if (choice == 1) {
        replay();
    }

    return 0;
}

这个代码使用了 `Step` 结构体来保存每一步的信息，使用了 `steps` 数组来保存所有的步骤，使用了 `stepCount` 变量来保存当前步骤的数量。在每次落子时，会将当前步骤保存到 `steps` 数组中，落子结束后会检查是否有玩家获胜或者棋盘已经下满，如果有则结束游戏。在游戏结束后，会提示用户是否要回放对局，如果用户输入 `1` 则进行对局回放，否则退出程序。