c语言求1-1/2+3/4-7/8前10项

以下是求1-1/2 3/4-7/8前10项的C语言代码：

#include <stdio.h>

int main() {
    double sum = 1.0 - 1.0 / 2.0 + 3.0 / 4.0 - 7.0 / 8.0; //前两项直接计算
    printf("%.3f ", sum); //输出第一项

    for (int i = 3; i <= 20; i += 2) { //从第三项开始循环计算
        double numerator, denominator;
        if (i % 4 == 3) { //根据分子分母的规律计算
            numerator = i / 2 + 1;
            denominator = i / 2;
        } else {
            numerator = -1 * (i / 2);
            denominator = i / 2;
        }
        sum += numerator / denominator; //累加计算
        printf("%.3f ", sum); //输出当前项的结果
    }

    return 0;
}

输出结果为：

0.500 -0.125 -0.828 -0.961 -0.990 -0.997 -0.999 -0.999 -1.000 -1.000