用c++代码写游泳时间之差的计算

在C++中，你可以创建一个函数来计算两个游泳者完成比赛的时间差。假设你有两个结构体Swimmer，包含姓名(name)和完成时间(time)，你可以这样做：

#include <iostream>
#include <string>

struct Swimmer {
    std::string name;
    double time; // 时间以秒为单位
};

double calculateTimeDifference(Swimmer swimmer1, Swimmer swimmer2) {
    return swimmer2.time - swimmer1.time;
}

int main() {
    Swimmer swimmerA = {"Alice", 500.0};
    Swimmer swimmerB = {"Bob", 480.0}; // 假设这是两个游泳者的成绩

    double timeDiff = calculateTimeDifference(swimmerA, swimmerB);
    
    std::cout << "Swimmer " << swimmerA.name << " finished " 
              << timeDiff << " seconds ahead of " << swimmerB.name << "." << std::endl;

    return 0;
}

在这个例子中，`calculateTimeDifference`函数接收两个`Swimmer`对象作为输入，并返回它们之间的时间差。在`main`函数中，我们创建了两个游泳者实例并计算了他们的成绩差距。