JAVA实现n个数的求和,最大值最小值
时间: 2023-05-23 17:04:56 浏览: 99
A:以下为JAVA代码实现n个数的求和、最大值和最小值:
```java
import java.util.Scanner;
public class SumMinMax {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
int n = scanner.nextInt();
int sum = 0;
int max = Integer.MIN_VALUE;
int min = Integer.MAX_VALUE;
for (int i = 0; i < n; i++) {
int num = scanner.nextInt();
sum += num;
if (num > max) {
max = num;
}
if (num < min) {
min = num;
}
}
System.out.println("Sum: " + sum);
System.out.println("Max: " + max);
System.out.println("Min: " + min);
}
}
```
在该代码中,首先通过Scanner对象获取用户输入的n个数,使用循环结构遍历每个数,同时记录数的累加和、最大值和最小值,最后输出这些结果。