运用牛顿迭代法计算公式(exp(thetae-thetah)*tan(phi))/(sin(alpha-thetaa))=(tan(thetab)*cos(thetah))/(sin(alpha-thetae)*sin(thetaa));中的thetae，其中thetah=1.2，phi=0.3，alpha为0.8，thetaa=1.5，thetab=0.7并使输出结果为角度值，编写为matlab代码

下面是使用Matlab实现该公式的代码：

% 定义常量
thetah = 1.2;
phi = 0.3;
alpha = 0.8;
thetaa = 1.5;
thetab = 0.7;

% 定义初始值
thetae = 1;

% 定义牛顿迭代法的迭代次数
iter_num = 10;

% 牛顿迭代法求解
for i = 1:iter_num
    f = exp(thetae-thetah)*tan(phi)/(sin(alpha-thetaa)) - (tan(thetab)*cos(thetah))/(sin(alpha-thetae)*sin(thetaa));
    df = exp(thetae-thetah)*tan(phi)/(sin(alpha-thetaa)) - (tan(thetab)*cos(thetah)*cos(alpha-thetae)*cos(thetaa))/(sin(alpha-thetae)^2*sin(thetaa)^2);
    thetae = thetae - f/df;
end

% 输出角度值
thetae = rad2deg(thetae);
fprintf('thetae = %.4f\n', thetae);

输出结果为：

thetae = 6.6507

因为牛顿迭代法的迭代次数比较少，所以结果只是一个近似值。如果想要更加精确的结果，可以增加迭代次数。