R语言如何让xgb.plot.shap(X.train,model=Heart.xgb,features=c("PM2.5","PM10","NO2","O3"),n_col=3,c画出的四个图放在同一行
时间: 2024-12-14 20:19:18 浏览: 10
在R语言中,`xgb.plot.shap()` 函数来自于`xgboost`包,用于可视化XGBoost模型的SHAP值(Shapley Additive Explanations)。如果你想将`xgb.plot.shap()`绘制出的关于特征"PM2.5", "PM10", "NO2", 和 "O3" 的四张图放在同一行,可以使用`gridExtra`包中的`grid.arrange()`函数。首先确保已经安装了这两个包:
```r
install.packages(c("xgboost", "gridExtra"))
```
然后按照以下步骤操作:
1. 对数据集`X.train`应用 SHAP 解释,并保存结果到变量如`shap_values`:
```r
library(xgboost)
library(shap)
# 计算Shapley值
shap_values <- shap(model = Heart.xgb, data = X.train, type = "tree")
```
2. 分别对每个特征生成`xgb.plot.shap()`图形:
```r
pm2_5_plot <- xgb.plot.shap(shap_values, feature = "PM2.5", ncol = 1)
pm10_plot <- xgb.plot.shap(shap_values, feature = "PM10", ncol = 1)
no2_plot <- xgb.plot.shap(shap_values, feature = "NO2", ncol = 1)
o3_plot <- xgb.plot.shap(shap_values, feature = "O3", ncol = 1)
```
3. 将这四个图组合在同一行:
```r
combined_plots <- grid.arrange(pm2_5_plot, pm10_plot, no2_plot, o3_plot,
ncol = 3, heights = c(1, 1, 1)) # nrow自适应调整列数
```
最后,显示`combined_plots`:
```r
grid::grid.draw(combined_plots)
```
这样就实现了四幅图在同一行展示了。
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